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valina [46]
4 years ago
14

Use completing the square to solve the equation x^2+16x=-44.

Mathematics
2 answers:
Sidana [21]4 years ago
7 0

Step-by-step explanation:

our equation is x²+16x = -44

  • x²+16x= -44
  • x² is the first term so weill have in the middle 2*x* a number
  • x²+2*x*8 = -44
  • the third term is 8² wich is 64 so we will add it in both sides
  • x²+2*x*8+64 = -44+64
  • (x+8)² = 20

Now that we have completed the perfect square let's solve the equation

  • (x+8)² = 20
  • x+8 = \sqrt{20}or x+8= -\sqrt{20}
  • x = -8+\sqrt{20} or x =  -8- \sqrt{20}

so the first answer is the correct one

64; 8 +/- \sqrt{20}

PolarNik [594]4 years ago
6 0
Rewrite the equation
x^2+16x=-44

Complete the square on the left hand side and add the answer to the right side to balance it
(16/2)^2=(8)^2=64
x^2+16x+64=-44+64

Simplify the equation
(x+8)^2=20

Find the roots of both sides
x+8=4.5 to nearest tenth
x=4.5-8
x=-3.5

Hope it helps

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90+42=132

180-132=48

<span>The missing angle is 48°</span>
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Drag and drop each pair of lines into the correct category to indicate whether the pair of lines are parallel, perpendicular, or
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4a) 4 1/6

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In a lab experiment, 80 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to doub
Effectus [21]

Answer:

The hourly growth rate is of 4.43%.

The function showing the number of bacteria after t hours is P(t) = 80(1.0443)^t

Step-by-step explanation:

Equation of population growth:

The equation for the population after t hours is given by:

P(t) = P(0)(1+r)^t

In which P(0) is the initial population and r is the growth rate, as a decimal.

The conditions are such that the number of bacteria is able to double every 16 hours.

This means that P(16) = 2P(0). We use this to find r.

P(t) = P(0)(1+r)^t

2P(0) = P(0)(1+r)^{16}

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1 + r = 2^{\frac{1}{16}}

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The hourly growth rate is of 4.43%.

80 bacteria are placed in a petri dish.

This means that P(0) = 80.

P(t) = P(0)(1+r)^t

P(t) = 80(1+0.0443)^t

P(t) = 80(1.0443)^t

The function showing the number of bacteria after t hours is P(t) = 80(1.0443)^t

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