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3 years ago

On a coordinate plane, an image rectangle has points (negative 5, 0), (5, 0), A prime (5, negative 5), (negative 5, negative 5).

Mathematics

2 answers:

Luden [163]3 years ago

7 0

Answer:(5/3,5/3)

Step-by-step explanation: I did the test ;D

aev [14]3 years ago

6 0

Answer:(5/3,5/3)

Step-by-step explanation: I did the test ;D

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3000(1.07)×3= 9,630.

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3 years ago

Need answer ASAP *MARKING BRAINLIEST

Rzqust [24]

Answer:

y=-2/3x +1

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

X2 - 6x + 12 and y = 2x - 4, algebraically are

olga_2 [115]

The solution is (4, 4)

Solution:

Given system of equations are:

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

Substitute eqn 2 in eqn 1

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

Solve by quadratic equation

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

Substitute x = 4 in eqn 2

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

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3 years ago

Find the volume of the triangular prism. 2.5 m 6 m 3.1 m

ahrayia [7]

Answer:

46.5

Step-by-step explanation:

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2 years ago