Answer: Oxygen and glucose are both reactants in the process of cellular respiration.
Explanation: Oxygen and glucose are both reactants in the process of cellular respiration. The main product of cellular respiration is ATP; waste products include carbon dioxide and water.
Answer:
21.4 L
Explanation:
Given data:
Volume of carbon dioxide produced = ?
Volume of oxygen = 37.4 L
Solution:
Chemical equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
It is known that,
1 mole = 22.414 L
There are 7 moles of oxygen = 7×22.414 = 156.9 L
There are 4 moles of carbon dioxide = 4×22.414 = 89.66 L
Now we will compare:
O₂ : CO₂
156.9 : 89.66
37.4 : 89.66/156.9×37.4 = 21.4 L
So from 37.4 L of oxygen 21.4 L of carbon dioxide is produced.
In organic compounds<span>, any atom that is not carbon or hydrogen is called a/an____. The abbreviation"R" in a chemical formula </span>represents<span> a functional group or a hydrocarbon portion of the molecule. i hoped that helped alittle</span>
A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.
<h3>What is a decomposition reaction?</h3>
A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.
- Step 1: Write the balanced equation for the decomposition of KHCO₃.
2 KHCO₃(s) → K₂CO₃(s) + CO₂(g) + H₂O(l)
The mass loss of 0.275 g is due to the gaseous CO₂ that escapes the sample.
- Step 2: Calculate the mass of KHCO₃ that formed 0.275 g of CO₂.
In the balanced equation, the mass ratio of KHCO₃ to CO₂ is 200.24:44.01.
0.275 g CO₂ × 200.24 g KHCO₃/44.01 g CO₂ = 1.25 g KHCO₃
- Step 3: Calculate the mass percentage of KHCO₃ in the sample.
There are 1.25 g of KHCO₃ in the 1.775 g sample.
%KHCO₃ = 1.25 g/1.775 g × 100% = 70.4%
A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.
Learn more about decomposition reactions here: brainly.com/question/14219426
Answer:
Newton's first and third law of Motion
Explanation:
The laws applying in the example Newton's first and third laws of Motion.
- The first law states that any object at rest (ie. not moving) will stay at rest until it is forced to move by an external force. In this case, said force were the propulsion gases ignited.
- As the hot gases were pushed out from the engine nozzle, there was another force <em>equal in magnitud but opposite in direction</em> (as the gases went down, that force went upwards), said force is directly responsible for the rocket taking off. That is an example of the third law.
