1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hammer [34]
2 years ago
8

Write the electron configuration for the elements whose atomic numbers are the following:

Chemistry
1 answer:
andreev551 [17]2 years ago
6 0

Answer:

3= Lithium (Li) = [He] 2s1

6= Carbon (C) = [He] 2s2 2p2

8=Oxygen (O)= [He] 2s2 2p4

13=Aluminium (Al)= [Ne] 3s2 3p1

U 2 can help me by marking as brainliest.........

You might be interested in
17 Two substances in a mixture differ in density and particle size. These properties can be used to(1) separate the substances
belka [17]
If they're different sizes and densities, you are able to separate the substances. 
6 0
3 years ago
Read 2 more answers
How many significant digits are in 89015
Lilit [14]

Answer:

Total 5 significant digits.

Explanation:

Significant digits are the numbers that give a meaningful contribution. For example, digit 013 has the 2  significant digits and zero is not a significant digit because digits 1 and 3 give meaningful contribution but digit zero does not value meaningful contribution. Similarly, the 89015 has a total of 5 significant digits and these digits are the 8, 9, 0, 1,  and 5.

6 0
3 years ago
What happens when a parking lot is built in a wetlands area?
Airida [17]
The ground could sink and sink holes could occur, otherwise the parking lot could simply break apart and wear faster
5 0
3 years ago
Read 2 more answers
When the paramagnetic [co(cn)6] 4– ion is oxidized to [co(cn)6] 3– , the ion becomes diamagnetic. however, when the paramagnetic
S_A_V [24]
Answer:  
Basically, paramagnetic and diamagnetic refer to the way a chemical species interacts with a magnetic field. More specifically, it refers to whether or not a chemical species has any unpaired electrons or not. 
 A diamagnetic species has no unpaired electrons, while a paramagnetic species has one or more unpaired electrons. 
 Now, I won't go into too much detail about crystal field theory in general, since I assume that you're familiar with it. 
 So, you're dealing with the hexafluorocobaltate(III) ion, [CoF6]3â’, and the hexacyanocobaltate(III) ion, [Co(CN)6]3â’. 
 You know that [CoF6]3â’ is paramagnetic and that [Co(CN)6]3â’ is diamagnetic, which means that you're going to have to determine why the former ion has unpaired electrons and the latter does not. 
 Both complex ions contain the cobalt(III) cation, Co3+, which has the following electron configuration 
  Co3+:1s22s22p63s23p63d6 
 For an isolated cobalt(III) cation, all these five 3d-orbitals are degenerate. The thing to remember now is that the position of the ligand on the spectrochemical series will determine how these d-orbtals will split. 
 More specifically, you can say that 
  a strong field ligand will produce a more significant splitting energy, Δ  a weak field ligand will produce a less significant splitting energy, Δ 
 Now, the spectrochemical series looks like this 
 http://chemedu.pu.edu.tw/genchem/delement/9.htmhttp://chemedu.pu.edu.tw/genchem/delement/9.htm 
 Notice that the cyanide ion, CNâ’, is higher on the spectrochemical series than the fluoride ion, Fâ’. This means that the cyanide ion ligands will cause a more significant energy gap between the eg and t2g orbitals when compared with the fluoride ion ligands. 
 http://wps.prenhall.com/wps/media/objects/3313/3393071/blb2405.htmlhttp://wps.prenhall.com/wps/media... 
 In the case of the hexafluorocobaltate(III) ion, the splitting energy is smaller than the electron pairing energy, and so it is energetically favorable to promote two electrons from the t2g orbitals to the eg orbitals → a high spin complex will be formed. 
 This will ensure that the hexafluorocobaltate(III) ion will have unpaired electrons, and thus be paramagnetic. 
 On the other hand, in the case of the hexacyanocobaltate(III) ion, the splitting energy is higher than the electron pairing energy, and so it is energetically favorable to pair up those four electrons in the t2g orbitals → a low spin complex is formed. 
 Since it has no unpaired electrons, the hexacyanocobaltate(III) ion will be diamagnetic.
6 0
3 years ago
Why is the atmosphere of Earth the outermost layer of the planet?
nasty-shy [4]
Option C but i am not sure
3 0
2 years ago
Read 2 more answers
Other questions:
  • Express 0.08010 in exponential notation to the proper significant figures
    11·1 answer
  • How many grams of solute are present in 1250 mL of a 1.34 M NaNO3 solution?
    14·1 answer
  • A student would like to determine how heating a liquid changes its volume. The student hypothesizes that the liquid will increas
    15·1 answer
  • Draw the Lewis structure for the trisulfur molecule. Be sure to include all resonance structures that satisfy the octet rule.
    11·1 answer
  • In the reaction Mg(s) + 2H2O(l) --> Mg(OH)2(s) + H2(g), what is the oxidation state of each H in H2(g)? A. +2 and –2 B. –1 an
    5·1 answer
  • Which of the following is a heterogeneous mixture
    8·1 answer
  • An 80.0 g sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and
    6·1 answer
  • Which substance can lead to addiction, or drug dependence, if abused?
    10·1 answer
  • What would be the anode<br> a magnesium and zinc galvanic cell?
    9·2 answers
  • How did the forensic sculptor/.facial reconstructionist assist in this case? <br><br><br> FORENSIC
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!