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3 years ago

How many moles of sulfur dioxide are in 2.26x10^33 sulfur dioxide molecules?

Chemistry

2 answers:

m_a_m_a [10]3 years ago

4 0

Answer:

It would be about 3 moles

Alexus [3.1K]3 years ago

3 0

Answer:moles = no. of molecules / Avogadro's number

= 2.26 x 10^33 / 6.022 x 10^23

= 3752906011

Round to significant figures which is 3 = 3.75 x 10^9 mol

Explanation:

The formula for finding how many moles of a substance when given the amount of molecules is: moles = number of molecules / Avogadro's number

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A certain indicator has a color chart that shows that when the indicator is yellow, the solution is acidic. What is true about a

bija089 [108]

It’s acidic?
It tastes sour
It has at least one hydrogen molecule

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3 years ago

The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres

Dima020 [189]

Answer:

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as $K_{p}$

$2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)$

Partial pressures at equilibrium:

$p^o_{H_2O}=0.070 atm$

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$p^o_{O_2}=0.0025 atm$

The equilibrium constant in terms of pressures is given as:

$K_p=\frac{(p^o_{H_2})^2\times (p^o_{O_2})}{(p^o_{H_2O})62}$

$K_p=\frac{(0.0035 atm)^2\times 0.0025 atm}{(0.070 atm)^2}=6.25\times 10^{-6}$

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

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3 years ago

What is the element that is in period 5 and group 3?

rjkz [21]

Answer:

Rubidium

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Viefleur [7K]

The answer is: True.

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The arrow has an obvious tail and arrowhead. The arrow points in the precise direction.

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Answer:

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Explanation:

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3 years ago