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3 years ago

How many moles of sulfur dioxide are in 2.26x10^33 sulfur dioxide molecules?

Chemistry

2 answers:

m_a_m_a [10]3 years ago

4 0

Answer:

It would be about 3 moles

Alexus [3.1K]3 years ago

3 0

Answer:moles = no. of molecules / Avogadro's number

= 2.26 x 10^33 / 6.022 x 10^23

= 3752906011

Round to significant figures which is 3 = 3.75 x 10^9 mol

Explanation:

The formula for finding how many moles of a substance when given the amount of molecules is: moles = number of molecules / Avogadro's number

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mixas84 [53]

Explanation:

As it is given that water level is same as outside which means that theoretically, P = 756.0 torr.

So, using ideal gas equation we will calculate the number of moles as follows.

PV = nRT

or, n = $\frac{PV}{RT}$

= $\frac{\frac{756}{760}atm \times 0.129 L}{0.0821 Latm/mol K \times 298 K}$

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mass = 0.0104 g

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$P_{\text{water vapor}}$ = 24 mm Hg

= $\frac{24}{760}$ atm

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= 0.0056 mol

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Therefore, calculate the percentage yield as follows.

Percent yield = $\frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100$

= $\frac{0.01013 g}{0.0104 g} \times 100$

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IceJOKER [234]

Answer:

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Explanation:

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