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vagabundo [1.1K]
4 years ago
15

Write an equation of a parabola that opens to the right, has a vertex at the origin, and a focus at (7, 0.

Mathematics
1 answer:
satela [25.4K]4 years ago
6 0
If a parabola opens to the right, then we know it is with respect to y and it's positive.

With vertex (h, k), we can write the equation as:
(y - k)^{2} = 4a(x - h)

Replacing (h, k) with (0, 0), we get:
y^{2} = 4ax

Now, the focus is a point (a, 0) on the parabola, such that its length from any point on the parabola is equidistant to the moving point on the parabola and the directrix, often noted as: x or y = -a

We're given the focus is: (7, 0)
The focus in its most general term is (a, 0), for when the vertex is at the origin.
Thus a = 7.

\text{Equation: } y^{2} = 28x
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4 years ago
Laura, Jose, and Keith have a total of $118 in their wallets. Jose has $8 more than Laura, Keith has 3 times what Laura has. How
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Jose = 8+ x
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So the total is equal to
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118= 5x + 8
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4 0
3 years ago
What is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B25%7D" id="TexFormula1" title="\frac{1}{25}" alt="\frac{1}{25}" align
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Answer: 0.04
Explanation:
Divide 1 by 25 and you’ll get 0.04
8 0
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