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2 years ago

If y varies directly as x, and y = 12 when x = 72, then what is the value of x when y = 3 ?

Mathematics

2 answers:

qwelly [4]2 years ago

8 0

Answer:

x = 18

Step-by-step explanation:

difference between y = 12, x=72 is 6

so if y = 3 then multiply 3×6 = 18

Vadim26 [7]2 years ago

7 0

Answer:

Step-by-step explanation:

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jok3333 [9.3K]

Answer:

$\large \boxed{\sf \ \ \ \dfrac{\sqrt{4025}-5}{2}=29.22144... \ \ \ }$

Step-by-step explanation:

Hello

<u>Let's note the original speed of the car v</u>

it means that in 1 hour he is going v miles

so to go 200 miles it takes ( in hour)

$\dfrac{200}{v}$

If the speed of the car is v+5 than to go 200 miles it takes (in hour)

$\dfrac{200}{v+5}$

and this time is one hour less so we can write

$\boxed{\sf \ \ \dfrac{200}{v+5}=\dfrac{200}{v}-1 \ \ }$

We can multiply by v(v+5) both parts of the equation so

$200v=200(v+5)-v(v+5)\\\\200v=200v+1000-v^2-5v\\\\v^2+5v-1000=0$

$\Delta=b^2-4ac=5^2+4*1000=4025\\\\ \text{There are potential solutions }\\\\\ \ \ \ \ x_1=\dfrac{-5-\sqrt{4025}}{2}\\\\\ \ \ \ \ x_2=\dfrac{-5+\sqrt{4025}}{2}$

Only one is positive and this is is

$x_1=\dfrac{\sqrt{4025}-5}{2}=29.22144...$

So the original speed is 29.22144... mph

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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