1.50c + 2.50a = 1100
c + a = 500
multiply the second equation by -1.50
1.50c + 2.50a = 1100
-1.50c - 1.50a = -7.50
1.326 grams of NH3 are required to produce 4.65 g of HF.
Step-by-step explanation:
Balanced chemical reaction is written first to know the number of moles taking part in original reaction.
NH3 +3 F2 ⇒3 HF + NF3
Given:
mass of HF = 4.65
First the number of moles of HF in 4.65 grams is calculated by using the formula:
number of moles (n) = 
atomic mass of HF = 20 grams/mole
putting the values in the above equation number of moles can be found.
n = 
= 0.235 moles of HF are given.
From the equation it can be said that:
1 mole of NH3 reacts to form 3 moles of HF
so, x moles of NH3 would react to form 0.235 moles of HF
= 
3x = 0.235
x = 
x = 0.078 moles of NH3 is required.
The moles are converted to mass by applying the formula:
mass = atomic mass X number of moles (atomic mass of NH3 = 17 grams/mole)
putting the values in the formula
mass = 17 X 0.078
mass = 1.326 grams
Triangle A:
y = 57.5°
x = 57.5°
Triangle B:
y = 5
x = 6.5
Triangle C:
... I apologize but I do not know what Triangle C is. Sorry!!
Triangle D:
z = 30°
x = 90°
(x+20) = 110°
SORRY THAT TOOK SO LONG--
Answer:
Where is the graph my friend??
Answer:
y = 24
Step-by-step explanation:
Step 1:
y = - 6x Equation
Step 2:
x = - 4 Given
Step 3:
y = - 6 ( - 4 ) Input x value
Answer:
y = 24
Hope This Helps :)