Answer:

Step-by-step explanation:
Hi there!
<u>What we need to know:</u>
- Linear equations are typically organized in slope-intercept form:
where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)
- Parallel lines will always have the same slope but different y-intercepts.
<u>1) Determine the slope of the parallel line</u>
Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

Switch the sides

Divide both sides by 2 to isolate y

Now that this equation is in slope-intercept form, we can easily identify that
is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope
. Plug this into
:

<u>2) Determine the y-intercept</u>

Plug in the given point, (4,0)

Subtract both sides by 6

Therefore, -6 is the y-intercept of the line. Plug this into
as b:

I hope this helps!
A=a+b/2·h=9+4/2·3.5=22.75
Hoped I helped!
Answer:
x ≈ 3.1 ft
Step-by-step explanation:
The segment from the centre to the chord is a perpendicular bisector, thus
The triangle is right with base =
x
Applying Pythagoras' identity to the right triangle, then
(
x )² + 1.4² = 2.1²
x² + 1.96 = 4.41 ( subtract 1.96 from both sides )
x² = 2.45 ( multiply both sides by 4 )
x² = 9.8 ( take the square root of both sides )
x =
≈ 3.1 ft ( to the nearest tenth )
13.5 inches, because if you add 4.5x4 or 9x2 it equals 18, then you just subtract 4.5 from 18 and it’s 13.5
Answer:
Step-by-step explanation:
To be able to draw a conclusion from the data given, lets find out the p value using the t score and this will be used to make a conclusion.
If the p value is less than 0.05 then, we will reject the null but if otherwise we will fail to reject the null.
Using a p value calculator with a t score of 2.83, significance level 0.05 and the test is a two tailed test, the p value is 0.004655 which is less than 0.05 and the result is significant.
This we will reject the null hypothesis H0:p∗=1/2 for this data set.