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andrezito [222]
3 years ago
7

1

Mathematics
2 answers:
Shtirlitz [24]3 years ago
8 0

Answer:B. D.

Step-by-step explanation:

Took assignment

Blizzard [7]3 years ago
6 0

Answer:

Which statements are true about the inequality x less-than negative one-fourth and its graph? Check all that apply.

x = negative one-fourth is part of the solution set.

The arrow on the graph points to the left.

The arrow on the graph points to the right.

There is an open circle on the graph at Negative one-fourth.

There is a closed circle on the graph at Negative one-fourth.

The answer is B and D

Step-by-step explanation:

got it right on edg

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swat32
Since 1 oz is equal to 28.4 g and 1 kg is equal to 1000 g that means that 3521.12 kg are equal to 100 oz 
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Find the length of an arc of an 8" radius circle if the arc measures 45°.
kirza4 [7]
The area of  sector is calculated by the product of area of the circle and the sector angle. It is expressed as follows:

Area = πr² (α/360)
Area = π(8)²(45/360)
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Hope this answers the question. Have a nice day. Feel free to ask more questions.
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I can’t figure this out. Help!
77julia77 [94]

Answer:

Your answer should be x = \frac{48}{7}.

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2 years ago
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sorry if you can’t see BUT PLEASE HELP IM TIMED AND MY TEACHER IS GOIGN TO SUBMIT IT PLS ANSWER ONE BY ONE
Elan Coil [88]

Answer:

7.) a. 84 hundredths

8.) 6(.36)= 2.16 meters

9.) 9.40÷4= 2.34 meters

I cant see 10 clearly

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7 0
3 years ago
Why can’t we use the rules for exponents when the bases are not common?
Kazeer [188]

Answer:

Ok, the rules of the exponent come from a logic construction.

If we have x^n

this means that n is multiplied by itself n times.

If we decompose n into a + b, we have:

x by itself a times, and then x by itself b times, and for how the product works, this is equivalent:

if n = 5, a= 2 and b = 3

x^5 = (x*x*x*x*x)   5 times-

x^5 = x^(2 + 3) = (x^2)*(x^3) = (x*x*)*(x*x*x) = x*x*x*x*x = x^5

And the same for the other rules:

(x^n)^b = x^n*b and such.

Obviusly, this only works when we have a common base.

So the correct answer is that we constructed the exponential rules in a way that only can be used when we have a common base, and this happens because to construct them, we started with common bases.

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