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4vir4ik [10]
3 years ago
12

Find the value of y for the given value of x

Mathematics
2 answers:
Olin [163]3 years ago
6 0
I think it is 9 i hope this helped
Mama L [17]3 years ago
6 0
Y = -9

Y=(1/2)(-18/1)
Y=(-18/2)
Y=-9
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10 pounds of soil are needed to
Wewaii [24]

Answer:

40/3

Step-by-step explanation:

w = weight of soil needed

f = number of flower beds

a = constant value

w = a * f

<em>substitute</em>

10 = 6a

<em>simplify</em>

5/3 = a

w = (5/3)f

<em>plug in 8</em>

w = (5/3)(8)

<em>simplify</em>

w = 40/3

3 0
3 years ago
What is the value of 1/2 of 2/3 of 3/4 of 4/5 of 5/6 of 6/7 of 7/8 of 8/9 of 9/10 of 1000?
Alenkasestr [34]

Answer:

it's 100

Step-by-step explanation:

9/10 of 1000 is 900, 8/9 of 900 is 800, 7/8 of 800 is 700, 6/7 of 700 is 600, 5/6 of 600 is 500, 4/5 of 500 is 400, 3/4 of 400 is 300, 2/3 of 300 is 200, and 1/2 of 200 is 100 which makes 100 the value of 1/2 of 2/3 of 3/4 of 4/5 of 5/6 of 6/7 of 7/8 of 8/9 of 9/10 of 1000? I hope this makes sense.

5 0
3 years ago
Sarah's mom takes the parkway to work it takes her 30 minutes to travel from mile marker 88th where she answers to her exit at m
pentagon [3]
121- 88 = 33 miles traversed in 30 minutes.
 
d = r*t
33 = r* (.5 hr)

Solve for r. Average speed will be in miles per hour. <span>
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
</span>
7 0
3 years ago
The histogram shows the distributions of essay scores for high school sophomores and juniors in a contest. Which comparison of t
goblinko [34]

Answer:

A=Both distributions are nearly symmetric

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A data set of 27 different numbers has a mean of 33 and a median of 33. A new data set is
Svetllana [295]

Answer:

Option D.

Step-by-step explanation:

Suppose that we have a set of N values:

{x₁, x₂, ..., xₙ}

The median is the value in the middle, and the mean is calculated as:

M = \frac{(x_1 + x_2 + x_3 ... + x_n)}{N}

Because here we have "the median" then we will assume that N is odd, and there is only one median, the value "k"  (if N was even, the median would be the mean of the two middle values, that case is really similar to the case where N is odd, so solving only one of the cases is enough)

Now we add 7 to all the values greater than the median

We subtract 7 to all values smaller than the median.

Then the median remains unchanged (because we did not add nor subtract anything to the median).

The new mean will be:

M' = \frac{(x_1 - 7) + (x_2 - 7) + ... + (x_{k}) + ... + (x_n + 7)}{N} = \frac{(x_1 + x_2 + ... + x_n) + (-7)*(n/2 - 0.5) + 7*(n/2 - 0.5)}{N}  = \frac{(x_1 + x_2 + ... + x_n)}{N} = M

So the mean does not change.

Because the mean is computed as the sum of the numbers divided by N, and the mean does not change, and N does not change, then the sum of the numbers does not change.

Finally, the standard deviation is computed as:

SD = \sqrt{\frac{(x_1 - M)^2 + ... + (xn - M)^2}{N} }

Because M does not change, if we add or subtract numbers to some of the values, the standard deviation will change (Because all the terms are squared, so the added and subtracted sevens don't cancel like in the previous cases)

Then the only value that does not have the same value in both the original and new data sets is the standard deviation.

6 0
3 years ago
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