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Nataliya [291]
3 years ago
13

Which equation represents the graphed function?

Mathematics
1 answer:
dezoksy [38]3 years ago
5 0

Answer:

C

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, - 3) and (x₂, y₂ ) = (2, 0) ← 2 points on the line

m = \frac{0+3}{2-0} = \frac{3}{2}

note the line crosses the y- axis at (0, - 3) ⇒ c = - 3

y = \frac{3}{2} x - 3 → C

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Simplify the following expression: (5x2 + 3x + 4) − (2x2 + 5x − 1). If the final answer is written in the form Ax2 + Bx + C, wha
algol13

Answer:

A = 3

Step-by-step explanation:

Given

(5x² + 3x + 4) - (2x² + 5x - 1)

Remove the parenthesis from the first and distribute the second by - 1

= 5x² + 3x + 4 - 2x² - 5x + 1 ← collect like terms

= 3x² - 2x + 5

In the form Ax² + Bx + C

with A = 3

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If the quotient of -20 and 4 is decreased by 3 what number results
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If function F is defined by f(x) = 3x^2 + 5, what is f(x-4)
shepuryov [24]

Answer:

The function f(x) when x=x-4 is f(x-4)=3x^2-24x+53  or f(x-4)=3x(x-8)+53

Step-by-step explanation:

Given function f is defined by f(x)=3x^2+5

Now to find the function f(x-4):

f(x)=3x^2+5

Put x=x-4 in the above function we get

f(x-4)=3(x-4)^2+5

f(x-4)=3(x^2-2(x)(4)+4^2)+5 (using the formula (a-b)^2=a^2-2ab+b^2)

f(x-4)=3(x^2-8x+16)+5

f(x-4)=3x^2-24x+48+5 (adding the like terms)

f(x-4)=3x^2-24x+53

f(x-4)=3x(x-8)+53

Therefore f(x-4)=3x^2-24x+53  or f(x-4)=3x(x-8)+53

The function f(x) when x=x-4 is f(x-4)=3x^2-24x+53  or f(x-4)=3x(x-8)+53

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3 years ago
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