Answer:
a. 9.5x + 6.5(x+c) < 8 when c>0
b. Must be one child more than the no. of adults.
Step-by-step explanation:
For Cinema 1:
for adult = $9.50
for child = $6.50
For Cinema 2:
Per person regardless of age = $8.00
First of all, we will find out the condition when per person rates in both cinema are equal.
Assume x = no. of adults
y = no. of children
Rate per person in Cinema I = Rate per person in Cinema II
(9.5x + 6.5y)/(x+y) = 8
9.5x + 6.5y = 8(x+y)
9.5x + 6.5y = 8x + 8y
9.5x-8x = 8y-6.5y
=> x = y
So rates are equal when no. of adults equals no. of children
For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8
Hence we form an inequality when y = x+c and c > 0
9.5x + 6.5(x+c) < 8 when c>0
Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.
Answer:
6.36 years (the .36 repeats), so rounded is 6.4.
Step-by-step explanation:
First, I'm going to convert all measurements to meters.
Since 1000 mm = 1 m, divide 44 by 1000.
44/1000 = 0.044 m
Since 100 cm = 1 m, divide 72 by 100.
72/100 = 0.72 m
Next, I'm going to setup an equation using y = mx + b.
b is the beginning amount which is 0.72.
m in the equation represents the rate which is 0.044.
y represents the total which is 1.
Plugin the numbers and solve for x.
1 = 0.044x + 0.72
1 - 0.72 = 0.044x + 0.72 - 0.72
0.28 = 0.044x
0.28/0.044 = 0.044x/0.044
6.36 = x
Dominics son is 45inches tall
<u>Step-by-step explanation:</u>
Let his sons height be 'h'
If Dominic is 72 inches and casts a shadow of 60 inches. His son casts a shadow of 50 inches.
Then We can say that,
h = 50 x (72/60)
h = 45 inches
Dominics son is 45inches tall
Answer:
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