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Lerok [7]
3 years ago
11

if anyone is willing to help me with my math homework I have 8 worksheets I need to get finished by tommorow if anyone is willin

g to help it would. mean the world to me I'm trying to pass my class thank you in advance! ​
Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0

Answer:

only if I know how, otherwise I'll try and help

Step-by-step explanation:

Svetradugi [14.3K]3 years ago
5 0
It depends what kind of math it is. Fractions, angles, or something else. I don’t want to give you wrong answers.
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How do you find the slope of (2, -6) & (-3, -4)
marta [7]

(-4)-(-6)/(-3)-2=

2/-5

4 0
3 years ago
Read 2 more answers
If the balance at the end of eight years on an investment of $630 that has been invested at a rate of 9% is $1,083.60, how much
Contact [7]
The interest is $453.60.

The total amount includes principal + interest.  The principal was 630 and the total amount was 1083.60.
1083.60 - 630 = 453.60.
3 0
3 years ago
Factorise the following equation: <img src="https://tex.z-dn.net/?f=6x%5E2%2B17x%2B5" id="TexFormula1" title="6x^2+17x+5" alt="6
RSB [31]

Answer:

(3x+1)(2x+5) is the answer

8 0
3 years ago
For each expression, select all equivalent expressions from the list.
ratelena [41]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's find the equivalent expressions ~

#1. PROBLEM

\qquad \tt \dashrightarrow \:11x - 4x + 10x

\qquad \tt \dashrightarrow \:21x - 4x

\qquad \tt \dashrightarrow \:17x

#2. PROBLEM

\qquad \tt \dashrightarrow \:2(1 + 8y)

\qquad \tt \dashrightarrow \:(2 \times 1) + (2 \times 8y)

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8 0
2 years ago
The graph of f ′ (x), the derivative of f(x), is continuous for all x and consists of five line segments as shown below. Given f
Nataliya [291]

The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.

Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.

By the fundamental theorem of calculus,

\displaystyle f(5) = f(0) + \int_0^5 f'(x) \, dx

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so

\displaystyle \int_0^5 f'(x) \, dx = \frac{5+2}2 \times 2 = 7

\implies \max\{f(x) \mid 0\le x \le5\} = f(5) = f(0) + 7 = \boxed{13}

8 0
2 years ago
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