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gayaneshka [121]
3 years ago
5

Help please! This really impacts my grade!! Hope you guys know the answers

Mathematics
1 answer:
Leokris [45]3 years ago
5 0

Answer: this dose not even make sense

Step-by-step explanation:

You only put a pdf

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HELP!! To find the quotient of two fractions, you first need to rewrite the division problem as an equivalent multiplication pro
sergey [27]
1. 5/6

2. 2/3 x 5/6

3. 2/3 x 5/6 = 10/18
Multiply the numerators— 2 x 5 = 10
Multiply the denominators—3x 6= 18

4. 10/18 = 5/9
Find the greatest common factor of 10 and 18 which is 2.
Divide the numerator by 2– 10/2 = 5
Divide the denominator by 2– 18/2 = 9

I hope this helps!
6 0
3 years ago
Can anyone help me? I am stuck on this question! it would mean the world if u helped me! <3
Oksana_A [137]

Answer:

I think the answer is 12

Step-by-step explanation:

5 0
3 years ago
Y = kx<br> x = 4, y = -3
Sindrei [870]

y= kx

k= y/x

k= -3/4

make the constant K the subject

6 0
3 years ago
Read 2 more answers
Please help me asap thank you so so so much u are the most amazing
bixtya [17]

The smallest angle would be 19 degrees. So option D is correct.

<h3>What is the sum of the octagon?</h3>

The sum of exterior angles of the regular octagon is 360 degrees.

Given;

The angles

x + 13 + 2x - 1 + 2x + 6 + 2x + 12 + 2x - 17 + 3x - 4 + 3x - 10 + 4x = 360

19x - 1 = 360

19x = 359

x = 18.89

The smallest angle would be

2x - 17 = 2(18.89) - 17 = 19

Learn more about angles;

brainly.com/question/13954458

#SPJ1

5 0
2 years ago
*^%Brainliest 15 pounds Question 5 (2 points)
galben [10]

Answer:

0

Step-by-step explanation:

Separate into two parts

\frac{4xy^{3} }{2xy^{2} }  +  \frac{8x^{2} {y}^{5} }{2x {y}^{2} }

Simplify:

This is for the first fraction

\frac{4x {y}^{3} }{2x {y}^{2} }  = (4 \div 2)(x \div x)( {y}^{3}  \div  {y}^{2} )

2(1)( {y}^{3 - 2} )

2{y}

Now for the second fraction:

\frac{8 {x}^{2} {y}^{3}  }{2x {y}^{2} }  = ( 8 \div 2)( {x}^{2}  \div x)( {y}^{5}   \div   {y}^{2} )

4( {x}^{2 - 1} )( {y}^{5 - 2} )

4x {y}^{3}

Add both parts together

2y + 4x {y}^{3}

To turn this into the said formula, that would become:

2 {x}^{0}  {y}^{1}  + 4 {x}^{1}  {y}^{3}

Where:

a=0

b=1

c=1

d=3

Any value with an exponent 0 except zero will be equal to 1

4 0
3 years ago
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