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3 years ago

Which statement is true?

Mathematics

2 answers:

Alona [7]3 years ago

8 0

Answer:

ABE =DBC by SAS

Step-by-step explanation:

here is the answer

out of those options the correct answer is not there but in the 3rd option correct it as <u>DBC</u>

AB=BD

EB=BC

<E=<C (given)

SAS

Bingel [31]3 years ago

3 0

Answer:

D. ABE =CBD by SSS

Step-by-step explanation:

Given that AB = BD and BE = BC, the lengths of AE and CD are equal to each other. Hence, triangles ABE and BCD are congruent by SSS Theorem. The answer is D.

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Answer:

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Step-by-step explanation:

300*29% = 87

87/ 1000 = 11.49 (symplified)

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Step-by-step explanation:

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3 years ago

Verify the identity. <br><br> tan x plus pi divided by two = -cot x

kogti [31]

Recall that sin(π/2) = 1, and cos(π/2) = 0,

$\bf \textit{Sum and Difference Identities}
\\\\
sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)
\\\\
sin(\alpha - \beta)=sin(\alpha)cos(\beta)- cos(\alpha)sin(\beta)
\\\\
cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta)
\\\\
cos(\alpha - \beta)= cos(\alpha)cos(\beta) + sin(\alpha)sin(\beta)\\\\
-------------------------------\\\\
$

$\bf tan\left(x+\frac{\pi }{2} \right)=-cot(x)\\\\
-------------------------------\\\\
tan\left(x+\frac{\pi }{2} \right)\implies \cfrac{sin\left(x+\frac{\pi }{2} \right)}{cos\left(x+\frac{\pi }{2} \right)}
\\\\\\
\cfrac{sin(x)cos\left(\frac{\pi }{2} \right)+cos(x)sin\left(\frac{\pi }{2} \right)}{cos(x)cos\left(\frac{\pi }{2} \right)-sin(x)sin\left(\frac{\pi }{2} \right)}\implies \cfrac{sin(x)\cdot 0~~+~~cos(x)\cdot 1}{cos(x)\cdot 0~~-~~sin(x)\cdot 1}
\\\\\\
\cfrac{cos(x)}{-sin(x)}\implies -cot(x)$

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3 years ago