Answer:
The angle between the 190 ft. side and the 330 ft. side is 
Step-by-step explanation:
<u>The Law of Cosines</u>
When we know the value of all sides of a triangle, we can compute all of its interior angles by using the Law of Cosines, which is a generalization of the Pythagoras's theorem. If a,b, and c are the known sides of a triangle and 
is the angle formed by sides a and b (opposite to c), then
We'll use the values a=190, b=330, c=280 because we want to compute the angle opposite to c
Answer:
In AMNO, n = 92 inches, N=119° and 20=20°. Find the length of m, to the nearest 10th of an inch In AJKL, j = 9.6 inches, k = 6.4 inches and I=8.4 inches. Find the measure of K to thelaearest degree. In AQRS. q = 49 cm, 7.1 cm and S=70°. Find the area of AQRS, to the nearest 10th of a square centimeter Find all angles, 0 = 0 < 360°, that satisfy the equation below, to the nearest 10th of a degree. 25 sino-1=0 Find all angles, 0 SC <360°, that satisfy the equation below, to the nearest tenth of a degree (if necessary). 12 sin C + 6 = 5 sin ( + 6
Step-by-step explanation:
I believe the answers are C. Acute (all angles less than 90 degrees) and E. Scalene (all 3 sides different values).
Answer:
12x - 15 = 6 -3x (add 3x to both sides)
15x - 15 =6 (add 15 to both sides)
15x= 21 (divide both sides by 15 to get x alone)
x= 1.4 (the answer)
The answer is 113 hope that helps
