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Jlenok [28]
3 years ago
15

2x + y = 3

Mathematics
1 answer:
miv72 [106K]3 years ago
3 0

Answer:

C) 5x=5

Step-by-step explanation:

Multiplying an equation by a number means multiplying all its terms by that number.

Multiplying equation one by 2,

2(2x+y=3)

4x+2y=6

Adding that to equation 2,

4x+2y=6

+ x-2y=-1

The result is 5x=5

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6 0
2 years ago
The function y = 14.75 +1.25(x - 2) can
MrMuchimi

Answer:

$1.25 per game

Step-by-step explanation:

7 0
3 years ago
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
Hello! How to do question 5 (iii)?
Colt1911 [192]

Answer:

using your brain you have to find it on your own

8 0
2 years ago
If f(x)=4x-2/3 what would f(a+3) be​
blsea [12.9K]

Answer:

it will look like this 4(a+3)-2/3

Step-by-step explanation:

look since the equation "a+3" replaced for the place of "x" in f(x), you replace it on the equation "4x- 2/3" and just solve

8 0
3 years ago
Read 2 more answers
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