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Paladinen [302]
3 years ago
13

Solve for x: 3 2x=5x-9

Mathematics
1 answer:
atroni [7]3 years ago
4 0
3+2x=5x-9
minus 2x both sies
3=3x-9
add 9 to both sides
12=3x
divide both sides by 3
4=x
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Ann weighs 259 pounds but is only 5 feet 3 inches tall. Betty is 6 feet tall. How much would you expect Betty to weigh if they h
Tom [10]

Answer:

D. 296.00 LBS

Step-by-step explanation:

We convert both heights to inches.

1 ft = 12 in.

5 ft 3 in = 5 × 12 in. + 3 in. = 63 in.

6 ft = 6 × 12 in. = 72 in.

\dfrac{63~in.}{259~lb} = \dfrac{72~in.}{x}

\dfrac{63x}{259} = 72~lb

x = \dfrac{259 \times 72~lb}{63}

x = 296~lb

Answer: D. 296.00 LBS

7 0
2 years ago
There are 8 sophomores on the academic team. At the last competition, they each took the math test. Their scores were 82%, 92%,
Sav [38]

Answer:

79%

Step-by-step explanation:

To find the median, you need to arrange the numbers in ascending order. Than pick the middle number. If there are two middle numbers then you add them together and then divide by 2.

3 0
3 years ago
Diana received 300 votes in the election for student council president. That was 60% of the students who voted in the election.
Helen [10]

Answer:

500 students.

Step-by-step explanation:

300 votes is 60%.

100%-60% is 40%

so 40% voted for the other person.

Work backwards:

x * 0.6=300

0.6x=300

x=300/0.6 which is 500.

500*0.4 is 200.

300+200 is 500.

Hope this helps :) I am terribly sorry if it is wrong or not using the number line.

7 0
3 years ago
Answer this plz!!!!!!!!!!
belka [17]

That's a trapezoid,

A = \frac 1 2 (b+B)h

A = \frac 1 2 (4+12) 4 = 32

Answer: 32

But say we didn't know the formula. We can chop out the 4 by 4 square and we have two 45/45/90 triangles side 4 left over, so two 4 by 4 squares,

A = 2(4)(4) = 32

We can think of this as 12 by 4 rectangle with two 4 by 4 right triangles chopped out:

A = 12(4) - 2(1/2)(4)(4) = 48 - 16 = 32


7 0
3 years ago
PLEASE HELP. Which is the best interpretation of the solution set for the compound inequality? 3/2x-1<2x + 4 or 3(2/3x + 1) &
Fudgin [204]
(3/2)x-1<2x+4
3x-2<4x+8
-2<x+8
-10<x
x>-10

3((2/3)x + 1) < 11
(3*2/3)x+1*3<11
2x +3<11
2x<8
x<4

so the compound equality is the set of all numbers which are >-10 or <4, which are D) all real numbers
5 0
4 years ago
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