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Mars2501 [29]
3 years ago
5

3.45 0.78 0.003 2 1.46 from least to greatest

Mathematics
2 answers:
svetlana [45]3 years ago
4 0

Answer:

Yes it is correct answer

otez555 [7]3 years ago
3 0

                                                        <u>Answer</u>

__________________________________________________________

<h2>0.003 - 0.78 - 1.46 - 2 - 3.45</h2>

<em>__________________________________________________________</em>

<u>Least to Greatest</u>

  1. <em> 0.003</em>
  2. <em>0.78</em>
  3. <em>1.46</em>
  4. <em>2</em>
  5. <em>3.45</em>

<em>__________________________________________________________</em>

<em>Hope this helps! <3</em>

<em>__________________________________________________________</em>

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Answer:

Step-by-step explanation:

We would use the t- distribution.

From the information given,

Mean, μ = 2950

Standard deviation, σ = 115

number of sample, n = 25

Degree of freedom, (df) = 25 - 1 = 24

Alpha level,α = (1 - confidence level)/2

α = (1 - 0.98)/2 = 0.01

We will look at the t distribution table for values corresponding to (df) = 24 and α = 0.01

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We will apply the formula

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2950 ± 2.492 × 115/√25

= 2950 ± 2.492 × 23

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If 2x + 5 = 8x, then 12x = ?A.5B.10C.15D.20
butalik [34]
<h2>Answer:</h2>10.\text{ Option B is correct}

<h2>Explanation:</h2>

Given the equation expressed as:

2x+5=8x

First, we need to calculate the value of "x" from the given expression.

Step 1: Given the equation 2x + 5 = 8x

Step 2: Subtract 5 from both sides:

\begin{gathered} 2x+5-5=8x-5 \\ 2x+\cancel{5}-\cancel{5}=8x-5 \\ 2x=8x-5 \end{gathered}

Step 3: Subtract 8x from both sides

\begin{gathered} 2x-8x=8x-8x-5 \\ -6x=\cancel{8x}-\cancel{8x}-5 \\ -6x=-5 \end{gathered}

Step 4: Divide both sides by -6

\begin{gathered} \frac{-6x}{-6}=\frac{-5}{-6} \\ x=\frac{5}{6} \end{gathered}

Step 5: Get the value of 12x. Substitute x = 5/6 into the expression to have:

\begin{gathered} 12x=12(\frac{5}{6}) \\ 12x=\cancel{12}^2(\frac{5}{\cancel{6}^1}) \\ 12x=2\times5 \\ 12x=10 \end{gathered}

Therefore the value of 12x is 10

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