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sukhopar [10]
3 years ago
13

(6.) 6x – 4(-2x + 7) + 8 = 8x-19

Mathematics
2 answers:
Fed [463]3 years ago
7 0

Answer:

\frac{1}{6}

Step-by-step explanation:

1. you distrubute the -4 to the -2x and +7.

2.you combine like terms.

3.you get X in one side of the equation.

4.You divide 1 by 6.

marissa [1.9K]3 years ago
5 0

Answer:

  • The required value of x will be 1/6

Step-by-step explanation:

We have been given that an expression that is 6x – 4(-2x + 7) + 8 =8x-19.

We have to find the value of x.

  • First of all, We will distribute the terms in simplest form.

6x – 4(-2x + 7) + 8 =8x-19

6x + 8x - 28 + 8 = 8x - 19

  • We will combine the like terms.

6x + 8x -20 = 8x - 19

6x + 8x - 8x = -19 + 20

6x + 0 = 1

6x + 0 = 1 x = 1/6

  • Therefore, the required value of x will be 1/6.
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You need to find the common primes...

18=2*3*3  and 72=2*2*2*3*3  so they have 2*3*3 in common and 

2*3*3=18

So 18 is the greatest common factor.
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4 years ago
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Which inequality is true 1.5 > 2 1/2, 1/2 > 0.5, -2.5 > -1.5, -3 1/2 > - 4.5
yawa3891 [41]

Answer: D

Step-by-step explanation:

(A. 1.5 > 2 1/2

(B. 1/2 > 0.5

(C. -2.5 > -1.5

(D. -3 1/2 > - 4.5

Step 1: Convert everything to decimals or fractions so its easier to see and make it less likely to get the question wrong

Method #1: Fractions

1.5= 1 1/2

0.5= 1/2

-2.5= - 2 1/2

-1.5= - 1 1/2

-4.5= -4 1/2

Now we have:

(A. 1 1/2 > 2 1/2 --> This is wrong because 1 1/2 is supposed to be less than 2 1/2.

(B. 1/2 > 1/2 This is also wrong. 1/2 is equal to 1/2; they are obviously the same.

(C. -2 1/2 > -1 1/2 This is wrong because, in negative numbers, its sort of backwards. For example, -2 is actually less than -1 because its farther away from 0. But if they were normal positive numbers, 2 would be bigger. But here, -2 1/2 is less than -1 1/2.

(D. -3 1/2 > - 4 1/2 This is correct. -3 1/2 is closer to 0 than -4 1/2, so it has to be bigger.

Solving the problem this way gets me to: Answer= D

Method #2: Decimals (remember: same numbers, different way of writing them!!!)

(A. 1.5 > 2.5 False. 1.5 is less than 2.5

(B. 0.5 > 0.5 False. 0.5 is equal to 0.5

(C. -2.5 > -1.5 False. -2.5 is farther away from 0 so its actually smaller.

(D. -3.5 > - 4.5 True. -3.5 is closer to 0.

Doing it this way also leads me to Answer= D.

Hope this helps :)) Also can i please have brainiest? I worked pretty hard on this :D

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Answer:

864

Step-by-step explanation:

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A function $f$ has a horizontal asymptote of $y = -4,$ a vertical asymptote of $x = 3,$ and an $x$-intercept at $(1,0).$ Part (a
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1. f has a horizontal asymptote at y=-4

This means that

\displaystyle\lim_{x\to\pm\infty}f(x)-(-4)=0

(for at least one of these limits)

2. f has a vertical asymptote at x=3

This means that f has a non-removable discontinuity at x=3. Since f is some rational function, there must be a factor of x-3 in its denominator.

3. f has an x-intercept at (1, 0)

This means f(1)=0.

(a) With

f(x)=\dfrac{ax+b}{x+c}

the second point above suggests c=-3. The first point tells us that

\displaystyle\lim_{x\to\pm\infty}\frac{ax+b}{x-3}+4=0=\lim_{x\to\pm\infty}\frac{ax+b+4x-3}{x-3}=0

In order for the limit to be 0, the denominator's degree should exceed the numerator's degree; the only way for this to happen is if a=-4 so that the linear terms vanish.

The third point tells us that

f(1)=\dfrac{a+b}{1-3}=0\implies a=-b\implies b=4

So

f(x)=\dfrac{-4x+4}{x-3}

(b) Since

f(x)=\dfrac{rx+s}{2x+t}=\dfrac12\dfrac{rx+s}{x+\frac t2}

we find that \dfrac t2=-3\implies t=-6, and r=a=-4 and s=b=4.

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