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3 years ago

SOLVE EQUATION solve for x | 3x+19 | =13 (absolute value)

Mathematics

2 answers:

egoroff_w [7]3 years ago

8 0

Answer:

x=-2 and -32/3

Step-by-step explanation:

|3x+19|=13

3x+19=13 and 3x+19=-13

x=-2 and x=-32/3

Nuetrik [128]3 years ago

4 0

Answer:

x = -2 x = -32/3

Step-by-step explanation:

| 3x+19 | =13

There are two solutions, one positive and one negative

3x+19 = 13 3x+19 = -13

Subtract 19

3x+19-19 = 13-19 3x+19 -19 =-13-19

3x = -6 3x = -32

Divide by 3

3x/3 = -6/3 3x/3 = -32/3

x = -2 x = -32/3

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3 years ago

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Step-by-step explanation:

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3 years ago

Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?

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Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

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Step-by-step explanation:

f(x)= $2x^{3}-26x-24$

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$2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\$

$=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\$

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x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

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4 years ago

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