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Vaselesa [24]
3 years ago
6

Find 6 times as many as 2 divided by 6

Mathematics
2 answers:
scoundrel [369]3 years ago
3 0

Rewrite this symbolically: 6(2/6) = 12/6 = 2 (answer)

An equally good approach would be to cancel the 6's, obtaining 2 (answer)

sineoko [7]3 years ago
3 0

Answer:

2

Step-by-step explanation:

We are given that 6 times as many as 2 divided by 6

We have to find the value of 6 times as many as 2 divided by 6

2 divided by 6

Then, we get

2\div 6=\frac{1}{3}

6 times of \frac{1}{3}=6\times \frac{1}{3}

Then, we get 2

Hence, 6 times as many as 2 divided by 6=2

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Di the products 40x 500 and 4x 600 have the same number of zeros? Explain
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They both don't have the same number of zero as the answer because you are doing 40x500 which 20000 and 4x600 which is 2400
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Solve for u, z, y, or t.<br>​
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3 years ago
Find the area of parallelogram ABCD given m A = 30 and the following measures.
Nuetrik [128]

Answer: SECOND OPTION

Step-by-step explanation:

The area of a parallelogram can be calculated with this formula:

A=bh

Where "b" is the of one base and "h" is the height.

You can observe in the figure that "b" and "h" are:

b=AB=4\sqrt{2}ft\\\\h=AX=3ft

Then, substituting these values into the formula, you get that the area of the given parallelogram is:

A=(4\sqrt{2}ft)(3ft)\\\\A=12\sqrt{2}ft^2

This matches with the second option.

4 0
2 years ago
Given the recursive formula find the first 4 terms for each. (not multiple choice) (MAFS.912.F-BF.1.3) A. An=an-1 3 when a1=5 B.
Neko [114]

Answer:

<h3>See explanations below</h3>

Step-by-step explanation:

1) Given the recursive function An=an-1 + 3 when a1 = 5, we are  to find the first four terms;

First term a1 = 5

a2 = a1 +3

a2 = 5 + 3

a2 = 8

a3 = a2 + 3

a3 = 8+3

a3 = 11

a4 = a3 + 3

a4 = 11 + 3

a4 = 14

<em>The first four terms are 5, 8, 11 and 14</em>

<em></em>

<em>2) </em>For the recursive function  An=an-1 + 2/3 when a1 = 1

a2 = a1 + 2/3

a2 = 1 + 2/3

a2 = 5/3

a3 = a2 + 2/3

a3 = 5/3 + 2/3

a3 = 7/3

a4 = a3 + 2/3

a4 = 7/3 + 2/3

a4 = 9/3

a4 = 3

<em>Hence the first four terms of the sequence are 2/3, 5/3, 7/3, 3</em>

<em></em>

3) For the recursive function An=an-1 + 12 when a1=30

a2 = a1 + 12

a2 = 30 + 12

a2 = 42

a3 = a2 +12

a3 = 42 + 12

a3 = 54

a4 = a3 + 12

a4 = 54+12

a4 = 66

<em>Hence the first four terms of the sequence are 30, 42, 54, 66</em>

3 0
2 years ago
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