Let us say that,
<span>A = perimeter of football field of the 1st
school</span>
B = perimeter of football field of the 2nd school
C = perimeter of football field of the 3rd school
So that:
A = 320 m
B = 360 m
C = 400 m
So the first thing we have to do to find for the minimum
laps to make is to divide every perimeter by the smallest one, therefore divide
all by 320 m, hence:
A’ = 1
B’ = 1.125
C’ = 1.25
Now multiply everything by a number such that all laps
will be a whole number, in this case multiply everything by 8:
A’ = 8
B’ = 9
C’ = 10
Hence the laps to run are:
<span>8, 9 and 10</span>
Answer:
For 7m^2: 8.4
For .5m^2: .6
For 12 liters of paint: 10m^2
and for 6.6: 5.5m^2
Answer:
4 a 1
Step-by-step explanation:
Se lee "4 a 1"
Perimeter = 2(Length) + 2(Width)
300 = 2L + 2W → 150 = L + W → 150 - L = W
Area = Length · Width
= L(150 - L) → = 150L - L²
There are 2 different methods for solving (depending on which math course you are taking).
<u>Calculus</u>: find the derivative, set it equal to zero, and solve for L.
= 150L - L² → 0 = 150 - 2L → 2L = 150 → L = 75
<u>Algebra</u>: find the vertex.
= - L² + 150L → L = -b/2a → L = -150/2(-1) → L = 75
Once you solve for L, plug it into the Perimeter equation to solve for W:
150 - L = W → 150 - 75 = W → W = 75
Answer: 75ft x 75ft
C
YOUR ANSWER IS C BECAUSE ITS EQULVILENT
