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3 years ago

HELP PLEASE THIS IS DUE MONDAY! :(( GIVING 25 POINTS !!!

Mathematics

2 answers:

Rufina [12.5K]3 years ago

8 0

Answer:

For 7m^2: 8.4

For .5m^2: .6

For 12 liters of paint: 10m^2

and for 6.6: 5.5m^2

elena-14-01-66 [18.8K]3 years ago

3 0

Answer:

a) 8.4

b) 0.6

Step-by-step explanation:

a) 1.2L=1m^2

8.4L = 7m^2

7 times 1.2 is 8.4

b) 1.2L=1m^2

0.6L=0.5m^2

1.2 times 0.5 or 1.2 divided by 2 is 0.6

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Jan.1 Jerome concocts a rumor and tells

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Number of people who have heard it
by the end of the day:

January 1 . . . . . 2
January 2 . . . . . 4
January 3 . . . . . 8
January 4 . . . . . 16
January 5 . . . . . 32
January 6 . . . . . 64
January 7 . . . . . 128
January 8 . . . . . 256
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February 1 . . . . . 4,294,967,296
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4 years ago

Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of tim

Xelga [282]

Answer: P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = $\frac{2.\pi}{B}$

C is the phase shift or horizontal shift: $\frac{C}{B}$

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

Amplitude:

a = $\frac{largest - smallest}{2}$

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = $\frac{6.9-4.4}{2}$

a = 1.25

b

A time period for Pluto is T=66 years:

66 = $\frac{2.\pi}{b}$

b = $\frac{\pi}{33}$

Vertical Shift

It can be calculated as:

d = $\frac{largest+smallest}{2}$

d = $\frac{6.9+4.4}{2}$

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

8 0

3 years ago

How to solve for a and b

murzikaleks [220]

$\bf \begin{cases}
3=a\cdot b^0\\
75=a\cdot b^2
\end{cases}\qquad b^0=1\implies 
\begin{cases}
3=a\cdot 1\implies 3=a\\
----------\\
75=a\cdot b^2\implies 75=3\cdot b^2\\\\
\frac{75}{3}=b^2\implies 25=b^2\\\\
\pm \sqrt{25}=b\implies \pm 5 = b
\end{cases}$

recall, anything raised to the 0, zero, power, is 1, with the sole exception of 0

8 0

4 years ago

* What is the slope of the line? 10) Your answer

Irina18 [472]

Step-by-step explanation:

i need more information to respond

5 0

3 years ago

PLSSS HELPP!!!REAALLY need it its'overdue

SVETLANKA909090 [29]

Answer:

2) slant height=15