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garik1379 [7]
3 years ago
10

on the coordinate plane, what is the length of the line segment that connects points at (5, 4) and (−3, −1) ? Enter your answer

in the box. Round to the nearest hundredth.
Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0
Distance between points
D=\sqrt{(y2-y2)^2+(x2-x1)^2}
<span>
points are (5, 4) and (−3, −1)
</span>
D=√(-1-4)^2+(-3-5)^2
D=√25+64
D=√89
D=9.433 units
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Fran has ''buy one get one free'' tickets to the comedy club. She is bringing 7 people, including herself. If the regular price
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Please answer this correctly
Luba_88 [7]

Answer:

5 and 4

Step-by-step explanation:

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Which trigonometric functions are negative in the fourth (IV) quadrant?
anzhelika [568]
<h3>Answers are: sine, tangent, cosecant, cotangent</h3>

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On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.

Since sine is negative, so is cosecant as this is the reciprocal of sine

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