3 years ago

What is the center of the circle: (x+3)^2+y^2=16 ?

Mathematics

1 answer:

Sergio [31]3 years ago

7 0

Answer:

the answer is (-3,0) or 4

Step-by-step explanation:

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4. solve e) 4^x-10.2^x+16=0 I think the dot means multiply?

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$subtitute\ 2^x=t > 0\\\\t^2-10t+16=0\\t^2-2t-8t+16=0\\t(t-2)-8(t-2)=0\\(t-2)(t-8)=0\iff t-2=0\ or\ t-8=0\\\\t=2\ or\ t=8\\\\t=2^1\ or\ t=2^3\\\\therefore\ 2^x=2^1\ or\ 2^x=2^3\\\\Answer:\boxed{x=1\ or\ x=3}$

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