Answer:
a) 615
b) 715
c) 344
Step-by-step explanation:
According to the Question,
- Given that, A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams
- Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.
Z = (x - mean)/standard deviation
Now,
For x = 4171, Z = (4171 - 3311)/860 = 1
- P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.
Next, multiply that by the sample size of 732.
- Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171
- For part b, use the same method except x is now 1591.
Z = (1581 - 3311)/860 = -2
- P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.
- For part c, we now need to get two Z scores, one for 3311 and another for 5031.
Z1 = (3311 - 3311)/860 = 0
Z2 = (5031 - 3311)/860= 2
P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772
approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.
It should be 9:30 P.M.
7:45+ 15= 8
1 hour 35 minutes - 15= 1 hour 20
8+ 1 hour 20 minutes= 9:20
9:20+ 10= 9:30 P.M.
I think its 8? someone correct me if im wrong.
Answer:
hmmmm lemme think. id say simplify the top and bottom then divide. im kinda busy rn so i cant do it. sorry bro but what grade is this and i could help you some more in the future ok :)
Step-by-step explanation:
Answer:
2/3 (0.6 repeating) pages per minute
Step-by-step explanation:
Divide the numerator (40) by the denominator (60).
You get 2/3 pages per minute.
