<span>I note that this problem starts out with "Which is a factor of ... " This implies that you were given several answer choices. If that's the case, it's unfortunate that you haven't shared them.
I thought I'd try finding roots of this function using synthetic division. See below:
f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation. Thanks.
Possible zeros of this poly are factors of 35: plus or minus 1, plus or minus 5, plus or minus 7. Use synthetic division; determine whether or not there is a non-zero remainder in each case. If none of these work, form rational divisors from 35 and 6 and try them: 5/6, 7/6, 1/6, etc.
Provided that you have copied down the function
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35 properly, this approach will eventually turn up 1 or 2 zeros of this poly. Obviously it'd be much easier if you'd check out the possible answers given you with this problem.
By graphing this function, I found that the graph crosses the x-axis at 7/2. There is another root.
Using synth. div. to check whether or not 7/2 is a root:
___________________________
7/2 / 6 -21 -4 24 -35
21 0 -14 35
----------- ------------------------------
6 0 -4 10 0
Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial. Thus, (x-3.5), or (x-7/2), is a factor.
Current year is 2016
born year is 1977
old
2016 - 1977
39 years
Answer:
The first loan L1 = $20,000
This is the loan with 3% simple interest
The second loan L2 = $4,000
This is the loan with 5.5% simple interest
Step-by-step explanation:
L1 + L2 = $24,000 ...(1)
4(3% of L1) + 4(5.5% of L2) = $3,280 ...(2)
Where the first term in equation (2) represents the total interest paid on loan 1 after 4 years
The second term represents total interest accruing to loan 2 after 4 years
From equation (1), we single out L1
L1 = 24,000 - L2
Substitute this value for L1 in equation (2)
288,000 + 10L2 = 328,000
L2 = $4,000
L1 = $24,000 - $4,000 = $20,000
Answer:
<h2>
y = 5.6</h2>
Step-by-step explanation:
From Thales' theorem:
