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Brilliant_brown [7]
3 years ago
12

3x/2-7=x/4-2 I know the answer is four but I don’t know how to get it

Mathematics
1 answer:
Levart [38]3 years ago
8 0

Answer:

X=4

Step-by-step explanation:

(3X/2) - (X/4) = 5

(6X-X)/4 = 5

(5X)/4 = 5

5X = 20

X = 4

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Answer:

First option:  3x^2-5x=-8

Second option: 2x^2=6x-5

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Step-by-step explanation:

Rewrite each equation in the form ax^2+bx+c=0 and then use the Discriminant formula for each equation. This is:

D=b^2-4ac

1) For 3x^2-5x=-8:

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Then:

D=(-5)^2-4(3)(8)=-71

Since D this equation has no real solutions, but has two complex solutions.

2) For 2x^2=6x-5:

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Then:

D=(-6)^2-4(2)(5)=-4

Since D this equation has no real solutions, but has two complex solutions.

3) For 12x=9x^2+4:

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Then:

D=(-12)^2-4(9)(4)=0

Since D=0 this equation has one real solution.

4) For -x^2-10x=34:

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D=(-10)^2-4(-1)(-34)=-36

Since D, this equation has no real solutions, but has two complex solutions.

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What must be true about the sides and angles of congruent triangles?
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