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Harrizon [31]
3 years ago
10

Find the product (4x-3y)(2x+5)

Mathematics
1 answer:
Llana [10]3 years ago
5 0

Answer:

8x²−6xy+20x−15y

Step-by-step explanation:

(4x−3y)(2x+5)

=(4x+−3y)(2x+5)

=(4x)(2x)+(4x)(5)+(−3y)(2x)+(−3y)(5)

=8x²+20x−6xy−15y

=8x²−6xy+20x−15y

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What is x in the following equation -3(-4x-3) = 20
choli [55]

Answer:

Step-by-step explanation:

-3(-4x-3) = 20

Opening bracket

12x + 9 = 20

12x = 20 - 9

12x = 11

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4 0
4 years ago
Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7
Dima020 [189]

Answer:

The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

\dfrac{\textrm factor of P}{\textrm factor Q} ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial ,  P = -7 , Q = 4

Now , \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}

I.e  \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q} = \frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }

Or, The rational zero are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1

Hence The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  Answer

7 0
4 years ago
Order the equations from least to greatest based on the number of solutions to each equation.
aleksandrvk [35]

In order it  goes like this

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so the question is the answer

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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