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3 years ago

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On a test, you correctly answer six 5-point questions and eight 2-point questions. You earn 92% of the possible points on the te

st. How many points p is the test worth?

1 answer:

Mandarinka [93]3 years ago

5 0

Answer:

50 points

Step-by-step explanation:

i looked it up, and the internet says 46 is 92% of 50.

also i like ur todoroki pfp

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Ahh please help me asap

Alina [70]

Answer:

10 $\sqrt5$

Step-by-step explanation:

8 0

3 years ago

QM Q9.) Write the standard form of the equation of the circle with the given center and radius.

pychu [463]

Hello there!

The standard form of the equation of a circle with center (h, k) and radius r is:

(x - h)² + (y - k)² = r²

So we have h = 4 and k = 3 and r = √5

So we just need to add these numbers to where they belong.

(x - 4)² + (y - 3)² = (√5)²

(x - 4)² + (y - 3)² = 5

Let me know if you have questions about the answer. As always, it is my pleasure to help students like you!

4 0

3 years ago

Find the differential of each function. (a) y = tan( 5t ) dy = Correct: Your answer is correct. (b) y = 5 − v2 5 + v2

Trava [24]

Answer:

$(a)$ $dy = 5sec^2(5t) \ dt$

$(a) \ dy = \frac{-20v}{(5+v^2)^2} \ dt$

Step-by-step explanation:

Given;

(a) y = tan(5t)

$(b) \ y = \frac{5-v^2}{5+v^2}$

Solving for (a)

y = tan(5t)

let u = 5t

⇒y = tan(u)

du/dt = 5

dy/du = sec²u

$\frac{dy}{dt} =\frac{dy}{du} *\frac{du}{dt} \\\\\frac{dy}{dt} = sec^2(u)*5\\\\\frac{dy}{dt} = 5sec^2(u)\\\\\frac{dy}{dt} = 5sec^2(5t)$

$dy = 5sec^2(5t) \ dt$

Solving for b;

let u = 5 - v²

du/dv = -2v

let v = 5+ v²

dv/du = 2v

$\frac{dy}{dv} = \frac{vdu - udv}{v^2} \\\\\frac{dy}{dv} = \frac{-2v(5+v^2) - 2v(5-v^2)}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-10v-2v^3-10v+2v^3}{(5+v^2)^2}\\\\$

$\frac{dy}{dv} = \frac{-10v-10v}{(5+v^2)^2}\\\\\frac{dy}{dv} = \frac{-20v}{(5+v^2)^2}\\\\dy = \frac{-20v}{(5+v^2)^2} dt$

4 0

3 years ago

A car travels 14km in 25mins . Find out how far the car can travel in 5 hours if the speed remains the same ?

jekas [21]

<h3><u>Answer :- </u></h3>

168 km ...

<h3><u>Explanation :- </u></h3>

It is given that the car travels 14km in 25 minutes..

Now , assume that the distance the car travel in 5 hours be x..

Since 1 hour = 60 minutes..
5 hours = 300 minutes ..

• Thus , The two given statements are :-

14km -----------------> 25 minutes..
And, x km -------------> 300 minutes..

<h3><u>We know that , </u></h3>

The distance travelled by car and the time taken by the car is directly proportional to each other....

<h3>So , </h3>

$\frac{14}{25} = \frac{x}{300}$

$= x = 168km$

• Hence , Car can travel 168km in 5 hours ..

Hope this helps you :)

6 0

2 years ago

Which function passes through the points (2, 3) and (4, 4)?

Rina8888 [55]

Answer:

C. y=1/2x+2

Step-by-step explanation:

1. Find the slope using the slope formula.

Slope formula: y2-y1/x2-x1

Let the y-value in the second ordered pair (4,4) be y2, and the 3 in the first ordered pair (2,3) be y1. 4 and 2 from these ordered pairs will be x2 and x1.

Plug these values into the equation and simplify.

4-3/4-2

=1/2

Slope is 1/2

2. Choose one of the ordered pairs and plug those numbers and the slope into the point-slope formula.

Point slope formula: y-y1=m(x-x1). M represents the slope, and the x1 and y1 represent the values of the ordered pair.

Let's use the pair (4,4).

y-4=1/2(x-4)

3. Simplify the equation to convert to y=mx+b format.

Multiply the inside of the parentheses by 1/2.

y-4=1/2x-2

Add 4 to both sides.

y=1/2x+2

3. C is your answer, for it matches what you found in the calculations.

5 0

3 years ago