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lorasvet [3.4K]
3 years ago
5

Expand and simplify (4x +3)(2x - 5

Mathematics
2 answers:
Scrat [10]3 years ago
8 0

Answer:

Equation simplifed= 8x^2-14x-15

Step-by-step explanation:

koban [17]3 years ago
4 0

<em>Answer:</em>

<em>=8x^2-14x-15</em>

<em>Step by-step explanation:</em>

<em>First you Expand=4x times 2xx-4 times 5x+3 times 2x+3(-5)</em>

<em>then you simplify to get. 8x^2-14x-15</em>

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If I could get help………
charle [14.2K]

Answer:

x1 = 3 \\ y1  = 10 \\ x2 = 5 \\ y2 = 12 \\ y - y1 =  \frac{y2 - y1}{x2 - x1} (x - x1) \\ y - 10 =  \frac{2}{2} (x - 5) \\ y = x - 5 + 10 = x + 5

enjoy it

8 0
3 years ago
A triangle has side lengths of (5k - 7) centimeters, (k - 4) centimeters, and
Yuki888 [10]

Answer:

-6m and -6k

Step-by-step explanation:

(5k - 7) = -2k (k - 4) = -4k + -2k = -6k. (3m - 9) = -6m.

7 0
2 years ago
Let x represent the number of television show episodes that are taped in a season. Enter an expression for the number of episode
Vinil7 [7]

Answer:

x=8 ???

Step-by-step explanation:

??? not 100% sure but im pretty sure ;w;

8 0
2 years ago
Read 2 more answers
Emily and Sarah had a total of $80. after Sarah spent 1/3 of her money and Emily spent $17, Emily had twice as much money as Sar
Phoenix [80]
<span> SO in total, Emily and Sarah had a total of 80 dollars in which Emily had twice as much as Sarah.
Let’s solve to find out how much their Money is.
=> Since the ratio of the given data is 2:1, 2 + 1 =3, so let’s divide 80 by 3
=> 80 / 3 = 26.667 ,
=> Emily has twice as this.
=> 26.667 * 2 = 53.33
=> Sarah has 26.67
Now, Sarah spent 1/3 of her money
=> 26.67 / 3 = 8.89 – her remaining money
Emily spent 17 dollars of her money
=> 53.33 – 17 = 36.33</span>



3 0
2 years ago
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
3 years ago
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