1. C (x+8)^2
2. D y=6^x
3. D t/2.35 ; 2.13 ft.
4. A (7h^2-2h)/2; 672 cm^2
5. A 4.50 h ; $7.88
For one and two you just have to plug in the numbers into the equation to see what works.
Three four and five you have to read the problems and come up with an equation to get your answer. Please comment if you need to see the work!
So the ratio is 100:60 and that simplified is 5:3. for every 5 blue there is 3 red
First : x=-5-y and then put x in the phrase above
Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let 
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.
![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)
So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
First you do distributive property.
2c + 8 = 0
Then subtract 8 with 0
2c = -8
Then divide -8/2
<h2>c = -4</h2><h2>Hope this helps :)</h2><h2 />
