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poizon [28]
4 years ago
8

Please show work for both problems

Mathematics
1 answer:
sukhopar [10]4 years ago
5 0

(1) The value of x is 25

(2) The measure of ∠CBD is 60°

Explanation:

(1) The given two angles are vertical angles. Since, vertical angles are equal, we can add the two angles to determine the value of x.

Thus, we have,

5x+15=6x-10

Subtracting 5x from both sides, we have

15=x-10

Adding 10 to both sides , we have,

25=x

Thus, the value of x is 25.

(2) It is given that the measure of ∠ABC = (x+7)° and ∠CBD = (2x+14)°

Since, these two angles are supplementary angles and supplementary angles add upto 90°

Thus, we have,

2x+14+x+7=90

Simplifying, we get,

3x+21=90

       3x=69

         x=23

Thus, substituting the value of x in ∠CBD = (2x+14)° to determine its value.

2x+14=2(23)+14=46+14=60

Thus, the measure of ∠CBD is 60°

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We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. (a) Find the probability th
Verizon [17]

Answer:

a) There is a 16.6% probability that doubles were rolled.

b) Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

c) There is a 30.55% probability that at least one die is a 1.

Step-by-step explanation:

The probability formula is the number of desired outcomes divided by the number of total outcomes.

(a) Find the probability that doubles were rolled. (i.e. the two outcomes are equal)

There are six desired outcomes: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)

There are 36 total outcomes. So:

P = \frac{6}{36} = 0.166

There is a 16.6% probability that doubles were rolled.

(b) Given that the roll resulted in a sum of 6 or less, find the conditional probability that doubles were rolled.

The following rolls result in a sum of 5 or less:

(1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1)

So, there are 15 total outcomes.

3 of them are doubled: (1,1), (2,2), (3,3). So

P = \frac{3}{15} = 0.2

Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

(c) Find the probability that at least one die is a 1

The following outcomes have at least one die that is 1:

(1,1), (1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(3,1),(4,1),(5,1),(6,1)

So, there are 11 desired outcomes out of 36.

P = \frac{11}{36} = 0.3055

There is a 30.55% probability that at least one die is a 1.

6 0
4 years ago
Please help meeee I would be happy
Tcecarenko [31]
It’s A!

GCF = Greatest Common Factor
So this means the last two wouldn’t work automatically and it’s A because one of the numbers only go up to the fourth power :)
5 0
2 years ago
Read 2 more answers
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