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kobusy [5.1K]
4 years ago
6

The scatter plot shows data collected on the number of students who get off the bus at the first and the last stop of various sc

hool bus routes. Which statement is true? A. The data in the scatter plot shows a negative linear correlation. B. The data in the scatter plot shows a nonlinear correlation. C. The data in the scatter plot shows a positive linear correlation. D. The data in the scatter plot shows no correlation.
Mathematics
2 answers:
yulyashka [42]4 years ago
8 0

Answer:I think it’s A but I’m not sure and atleast there is an answer to this

Step-by-step explanation:

Fudgin [204]4 years ago
3 0
What subject is this for
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<img src="https://tex.z-dn.net/?f=n%5E%7B2%7D%20%2B3n-12%3D6" id="TexFormula1" title="n^{2} +3n-12=6" alt="n^{2} +3n-12=6" align
Natalija [7]

Answer:

Step-by-step explanation:

n² + 3n - 18 = 0

n = [-3 ±√(3²-4(1)(-18)]/[2(1)] = [-3 ±√81]/2 = 3, -6

5 0
3 years ago
a patient receives 150 cc of medication in an IV drip over 4 hours.What is the rate per hour of this dose
goblinko [34]
I did 150 divided by 4 and I got 37.5 I think I'm using the right math lol
4 0
4 years ago
The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit in
Marina86 [1]

Answer:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3

We can express this formula like this:

\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2

\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

If we operate and we take out the 1/4 as a factor we got this:

\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}

We can cancel n^2 and we got

\lim_{n\to\infty} \frac{(n+1)^2}{n^2}

We can reorder the terms like this:

\lim_{n\to\infty} (\frac{n+1}{n})^2

We can do some algebra and we got:

\lim_{n\to\infty} (1+\frac{1}{n})^2

We can solve the square and we got:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

3 0
3 years ago
How many hours is in a day on Venus if a day lasts: <br><br> 5.81 x 10^3 hours
PSYCHO15rus [73]

Answer:

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Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
8.07<br> Rational or irrational
solniwko [45]

Answer:

Rational

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
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