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Sonbull [250]
3 years ago
15

A particle is moved along the x-axis by a force that measures 10/(1+x)^2 pounds at a point x feet from the origin. Find the work

(in ft-lb) done in moving the particle from the origin to a distance of 9 feet.
Physics
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

9 ft*lb

Explanation:

super simple but you just have to understand that the integral is going with the curve

work = integral a to b of f(x)dx = integral 0 to 9 of 10/(1+x)^2dx = 9ft*lb

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