A particle is moved along the x-axis by a force that measures 10/(1+x)^2 pounds at a point x feet from the origin. Find the work
1 answer:
You might be interested in
The ball takes 0.2 sec to travel the height of the window, which is 2 m.
Then the speed of the ball at that time was
We know that:
Where is the initial velocity.
So:
Then we have the equation for the position as a function of time.
Where
= initial position
r = position as a function of time
= initial velocity
g = acceleration of gravity
t = time.
If the ball is thrown from the ground then:
= 0 m
We want to find now the distance between the window and the ground.
When the ball reaches the bottom of the window t = 1.8s
So:
m
The window is 37,404 m high
Finally, to know how high the ball rises we must know at what moment the vertical velocity of the ball is zero.
Now we replace t in the position equation
The ball reaches up to 44.70 m in height.