Without friction, what force is needed to maintain a 1,000 kg car in uniform motion for 30 minutes?
1 answer:
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consider east-west direction along x-axis and north-south direction along y-axis
from the diagram
A = Ax i + By j = - (0.40 Sin60) i + (0.40 Cos60) j = - 0.35 i + 0.20 j
B = Bx i + By j = - 0.50 i + 0 j
Net displacement is given as
D = A + B
D = (- 0.35 i + 0.20 j ) + (- 0.50 i + 0 j )
D = - 0.85 i + 0.2 j
magnitude of displacement is given as
|D| = sqrt((- 0.85)² + (0.2)²)
|D| = 0.87 km
direction of displacement is given as
θ = tan⁻¹(0.2/0.85)
θ = 13.5 deg north of west
