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Karolina [17]
3 years ago
10

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

Mathematics
2 answers:
svetoff [14.1K]3 years ago
7 0

We want p-1 to divide p+p+p-k, i.e. 3p-k.

So, assume that we have a number \alpha such that

\dfrac{3p-k}{p-1}=\alpha

This implies that

3p-k=\alpha(p-1)=\alpha p-\alpha

Those two expression are equal if the correspondent coefficients are equal:

3p-k=\alpha p-\alpha \iff \begin{cases}3=\alpha\\-k=-\alpha\end{cases}\iff \begin{cases}3=\alpha\\k=\alpha\end{cases}

And it should be immediate to conclude the value for k from here.

s2008m [1.1K]3 years ago
4 0

Answer: none because i wont give it sped

r

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