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labwork [276]
4 years ago
9

How too solve (2x-3y)(4x-y) by multiplying polynomials by polynomials

Mathematics
1 answer:
Alex777 [14]4 years ago
4 0
(2x-3y) (4x-y)
Multiply the polynomials using distributive property.
(a+b)(c+d) = ac+ad + bc + bd
(2x-3y) (4x-y) = (2x) (4x) + (2x)(-y) + (-3y)(4x) + (-3y)(-y)
Apply plus/minus rule.
-(-a)=a and -(a)=-a
we get
=8x²-2xy-12xy+3y²
Add like terms
=8x²-14xy+3y²

Answer: 8x² - 14xy + 3y²
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What is the value of time, t, for the given values of distance, d, and rate, r?
Reika [66]
D 5.5 hours because distance = rate x time. So if you need to find time, you divide rate by the distance and 198 divided by 36 equals 5.5. Hope this helps

3 0
3 years ago
A van travels 125 miles on 5 gallons of gas. Find the distance the van can travel if the fuel tank contains 12 gallons of gas???
kobusy [5.1K]

Answer:

300 miles

Step-by-step explanation:

125/5 = 25 mpg

12 x 25 = 300 miles

8 0
3 years ago
- 6(x + 2) + 2x - 4 = 8(x - 2) + 8<br> does this have a solution if do why
kobusy [5.1K]

Answer:

Yes, there is a solution: - 2/3

Step-by-step explanation:

Step 1:

- 6 ( x + 2 ) + 2x - 4 = 8 ( x - 2 ) + 8

Step 2:

- 6x - 12 + 2x - 4 = 8x - 16 + 8

Step 3:

- 4x - 16 = 8x - 8

Step 4:

- 16 = 12x - 8

Step 5:

- 8 = 12x

Step 6:

- 8/12 = - 2/3

Answer:

- 2/3

Hope This Helps :)

6 0
3 years ago
Read 2 more answers
Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)
timama [110]
<h3>Answer:   c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\

With a = -5 and b = 4, we have

f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\

So,

f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\

Use algebra to solve for c

-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\

6 0
3 years ago
Is (2,3), (6,9), (10,12), (2,-3) a function
Igoryamba
No. If there are two of the same x, it’s not a function.
4 0
3 years ago
Read 2 more answers
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