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3 years ago

11

HELP ASAP I WILL MARK BRANLIEST!!!

1 answer:

Xelga [282]3 years ago

8 0

Answer:

0.14

Step-by-step explanation:

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7.52 divided by 64 =

Vaselesa [24]

0.1174
You could use a calculator

7 0

3 years ago

Whats 99/125 as a decimal?

vladimir2022 [97]

The answer to your question is .792 decimals

8 0

4 years ago

Read 2 more answers

Ha mush and Harry work as plumbers Harry earns a dollar more than more than 5/4 the amount gaming earns per hour the amount Harr

skad [1K]

Answer:

Hamish's earning = $20

Harry's earning = $26

Step-by-step explanation:

Given the following :

Let Harry's earning per hour = x

Let Hamish earning per hour = y

Harry earns a dollar more than more than 5/4 the amount hamish earns per hour;

Therefore,

x = 5/4y + 1

x - 5/4y = 1 - - - - (1)

the amount Harry earns per hour is $2 less than 7/5 the amount Hamish earns per hour

x = 7/5y - 2 - - - - (2)

Substituting (2) into (1)

7/5y - 2 - 5/4y = 1

7/5y - 5/4y = 1 + 2

7/5y - 5/4y = 3

Taking the L. C. M

(28y - 25y) / 20 = 3

28y - 25y = 60

3y = 60

y = 20

Substitute y = 20 into (1)

x - 5/4(20) = 1

x - 100/4 = 1

x - 25 = 1

x = 1 + 25

x = 26

y = Hamish's earning = $20

x = Harry's earning = $26

8 0

4 years ago

Alice has 1/5 as many cars as Sylvester has. Sylvester has 35 miniature cars. How many miniature cars does Alice have?

zalisa [80]

If im not wrong...
1/5 * 35 to get 1/5th of 35.
0.2*35=7

8 0

3 years ago

Prove it. this question is from trigonometry

konstantin123 [22]

Answer:

See below for step-by-step proof.

Step-by-step explanation:

$\textsf{Given expression}:$

$\cos^6 \theta+\sin^6 \theta$

$\textsf{Apply exponent rule} \quad a^{bc}=(a^b)^c:$

$\implies (\cos^2 \theta)^3+(\sin^2 \theta)^3$

$\textsf{Use the identity}\quad a^3+b^3=(a+b)^3-3ab(a+b):$

$\implies (\cos^2 \theta+\sin^2 \theta)^3-3 \cos^2 \theta\sin^2 \theta (\cos^2 \theta+\sin^2 \theta)$

$\textsf{Use the identity}\quad \sin^2 \theta + \cos^2 \theta=1:$

$\implies (1)^3-3 \cos^2 \theta\sin^2 \theta (1)$

$\implies 1-3 \cos^2 \theta\sin^2 \theta$

$\implies 1-3 (\cos \theta\sin \theta)^2$

$\textsf{Use the identity}\quad \sin 2 \theta=2 \sin \theta \cos \theta \implies \dfrac{1}{2}\sin 2 \theta= \sin \theta \cos \theta:$

$\implies 1-3 \left( \dfrac{1}{2}\sin 2 \theta\right)^2$

$\implies 1-\dfrac{3}{4} \sin^2 2 \theta$

$\textsf{Use the identity}\quad \sin^2 2\theta + \cos^2 2\theta=1 \implies \sin^2 2\theta=1-\cos^2 2\theta$

$\implies 1-\dfrac{3}{4} \left(1-\cos^2 2 \theta\right)$

$\implies 1-\dfrac{3}{4} +\dfrac{3}{4}\cos^2 2 \theta$

$\implies \dfrac{1}{4} +\dfrac{3}{4}\cos^2 2 \theta$

$\textsf{Factor out }\dfrac{1}{4}:$

$\implies \dfrac{1}{4}\left(1+3\cos^2 2 \theta\right)$

$\textsf{Use the identity}\quad \cos (4 \theta)=2 \cos^2 2\theta - 1 \implies \cos^2 2 \theta=\dfrac{1}{2}\cos 4 \theta+\dfrac{1}{2}:$

$\implies \dfrac{1}{4}\left(1+3\left(\dfrac{1}{2}\cos 4 \theta+\dfrac{1}{2}\right)\right)$

$\implies \dfrac{1}{4}\left(1+\dfrac{3}{2}\cos 4 \theta+\dfrac{3}{2}\right)$

$\implies \dfrac{1}{4}\left(\dfrac{5}{2}+\dfrac{3}{2}\cos 4 \theta\right)$

$\implies \dfrac{1}{4} \cdot \dfrac{1}{2}\left(5+3\cos 4 \theta\right)$

$\implies \dfrac{1}{8}\left(5+3\cos 4 \theta\right)$

6 0

2 years ago