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Mrrafil [7]
3 years ago
5

Some birds were flying and met a bird on their way. The bird greeted them; hello hundred! They said we are not hundred, we need

half of us plus you to make us hundred.
Question: How many birds were flying?
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0

Answer:

I'm not certain but it sounds as though there would be 150 birds flying .

Step-by-step explanation:

The first bird says we are not hundred, they need half their group population plus the second birds group population. So if we are trying to get 100 from two groups the easiest numbers would be to add 50 and 50. So if we have the second groups whole population be 50 birds then the first group's whole population must be 100. The first bird said half of us so that means half of 100 which would be 50. If you add half of the first groups population, which is 50(100/2=50), plus the second groups whole population (50), you get 100 birds. Which means if you add the first groups total population(100) with the second groups total population(50) you get 150 total birds flying.

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The distance between Joshua's home and school is 800 m. Joshua takes 5 min to walk
Fynjy0 [20]

Answer:

= 0.38 m/s

Step-by-step explanation:

▪Total distance = 800 m

5 min = 100 m

▪Remaining distance = 800 - 100 = 700 m

20 min = 700 m

▪Total time taken = 20 + 10 + 5 = 35 min

If 1 min = 60 sec

What about 35 min = ?

= 35 x 60

= 2100 sec

▪Average speed = TD ÷ TT

= 800 ÷ 2100

= 0.38 m/s

7 0
3 years ago
Tiana is a chemist who is making a chemical to add to swimming pools in order to make the water safer. She mixed two solid subst
Feliz [49]

Answer:

The chemically charges bionic dust formed by superconductor

Step-by-step explanation:

8 0
3 years ago
Inscribed circles on the arc; improvement answer is required in full.
e-lub [12.9K]

Answer:

The measure of an inscribed angle is half the measure of the intercepted arc

∠EFG creates Arc EDG

if ∠EFG is 1/2 arc EDG then 115° x 2 = 230°

A circle is 360°.

The remaining arc EFG is 360° - 230° = 130°

∠EDG is 1/2 of arc EFG so, 130° ÷ 2 = 65°

∠EDG = 65°

8 0
3 years ago
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
Use simultaneous equations to solve the following. Three kilograms of jam and two kilograms of butter cost $29 and six kilograms
artcher [175]

Answer:

The cost of 1kg jam is $7 and the cost of 1kg butter is $4

Step-by-step explanation:

Let jam = x

butter = y

3x + 2y = 29 -----(1)

6x + 3y = 54 -----(2)

(1)×2 ->

6x + 4y = 58 -----(3)

(3)-(2) ->

y = 4

suby=4into(2)

6x + 3(4) = 54

6x = 42

x = 7

(Correct me if i am wrong)

6 0
3 years ago
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