(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ = 
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
Answer:
12.22
Step-by-step explanation:
To find HI, you have to use tangent. tanx=
tan(42°)=
, then you multiply HI to both sides of equation and divide tan(42).
To get <em>HI</em>=
Which makes HI equal 12.2167
Answer:
a)6
b)v^2-u^2/2a
Step-by-step explanation:
a)Given that,
u=12
a= -6
s=9
We know that,
v^2=u^2+2as
or, v^2=(12)^2+2×(-6)×9
or,v^2=144-108
or,v^2=36
or, v=√36
∴v=6
(Ans)
b)If ,v^2=u^2+2as
then, u^2+2as=v^2
or,2as=v^2-u^2
or, s=v^2-u^2/2a
∴s=v^2-u^2/2a
Hope ya find it helpful.. Thanks a lot...
your answer is -1/100 (a fraction)
