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choli [55]
3 years ago
12

Find the solution of the following system of equations -5+2y=9 3x+5y=7

Mathematics
1 answer:
Rudiy273 years ago
5 0

Answer:

x=-\frac{28}{3}\\\\y=7

Step-by-step explanation:

Given the system of equations:

\left \{ {{-5+2y=9} \atop {3x+5y=7}} \right.

You can pply Substitution method:

First you must solve for "y" from the first equation:

-5+2y=9\\\\2y=9+5\\\\2y=14\\\\y=\frac{14}{2}\\\\y=7

Therefore, the second and final step to solve the system of equations is to substitute the value of "y" into the second equation and solve for "x":

3x+5(7)=7\\3x=7-35\\\\x=-\frac{28}{3}

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Round 287.9412 to the nearest tenth. Do not write extra zeros.
goldenfox [79]
Salutations!

<span>Round 287.9412 to the nearest tenth. 

Lets solve this!

To round to the nearest tenth, you need to know the tenth place--------

In the number, 287.9412, nine is in the tenth place. You need also make sure whether the number next to 9 is greater than 5 or not. 

</span><span>287.9412 =287.941=287.94=287.9=288=290

Thus, your answer is 290.

Hope I helped.
</span>
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1 + 4x + 6 - x = y What are m and b in the linear equation, using the common meanings of m and b?
chubhunter [2.5K]

Answer:

Step-by-step explanation:

it 28 by adding 6 +1 is 7 and times it by 4

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3 years ago
A baker bakes 752 muffins in a weekend. she sells the muffins in packs of 12. how many packs of muffins did she sell, how many d
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A parabola can be represented by the equation x2 = -20y.
aliya0001 [1]

Answer:

\mathrm{Parabola\:focus\:given}\:x^2=-20y:\quad \left(0,\:-5\right)

Step-by-step explanation:

Given the equation

x2 = -20y

A parabola is the locus of points such that the distance to a point the focus equals the distance to a line the directrix.

4p\left(y-k\right)=\left(x-h\right)^2 is the standard equation for an up-down facing parabola with vertex at (h, k), and a focal length |p|.

so

x^2=-20y

\mathrm{Switch\:sides}

-20y=x^2

\mathrm{Factor\:}4

4\cdot \frac{-20}{4}y=x^2

4\left(-5\right)y=x^2

\mathrm{Rewrite\:as}

4\left(-5\right)\left(y-0\right)=\left(x-0\right)^2

\left(h,\:k\right)=\left(0,\:0\right),\:p=-5

Parabola is symmetric around the y-axis and so the focus lies a distance\ p from the center (0, 0) along the y-axis.

\left(0,\:0+p\right)

=\left(0,\:0+\left(-5\right)\right)

\mathrm{Refine}

\left(0,\:-5\right)

Therefore,

\mathrm{Parabola\:focus\:given}\:x^2=-20y:\quad \left(0,\:-5\right)

Please check the attached figure too.

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