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pshichka [43]
2 years ago
15

A manufacturing company is considering a capacity expansion investment at the cost of $258,388 with no salvage value. The expans

ion would enable the company to produce up to 26,241 parts per year and the useful life of the additional capacity is seven years. Each part would generate $2.43 net profit and annual operating and maintenance costs are estimated at $28,599 per year. The market demand for the parts is unlimited, all parts produced will be sold. The MARR of the firm is 10%. The minimum annual production rate to make this investment justifiable is:

Business
1 answer:
Jobisdone [24]2 years ago
4 0

Answer:

33,610.42  units

Explanation:

For computing the minimum annual production rate first we have to determine the annual worth by using the PMT formula which is shown below:

Given that

Present value = $258,388

Interest rate = 10%

NPER = 7 years

Future value = $0

The formula is shown below:

= PMT(RATER;NPER;-PV;FV;type)

The present values comes in a negative

After solving this, the annual worth is $53,074.32

And, the annual operating maintenance cost is $28,599

So, the revenue should be

= $53,074.32 + $28,599

= $81,673.32

Now the minimum annual production rate is

= $81,673.32 ÷ $2.43

= 33,610.42  units

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Dobles Corporation has provided the following data from its activity-based costing system: Activity Cost Pools Estimated Overhea
Sati [7]

Answer:

Dobles Corporation

The unit product cost of product D28K is:

$144.01

Explanation:

a) Data and Calculations:

Activity Cost Pools    Estimated Overhead Cost   Expected Activity

Assembly                     $228,060                            18,000 machine hours

Processing orders         $34,068                              1,200 orders

Inspection                    $125,560                               1,720 inspection hours

Units of D28K produced per year = 420 units

D28K requirements:

Machine hours     460

Orders                    80

Inspections             10

Direct materials cost per unit = $48.96

Direct labor cost per unit = $25.36

Activity rate:

Assembly                     $228,060/18,000 = $12.67 per machine hour

Processing orders         $34,068/1,200 = $28.39 per order

Inspection                    $125,560/1,720 = $73 per inspection-hour

Cost of D28K:

Machine hours     460 * $12.67 =   $5,828

Orders                    80 * $28.39 = $22,712

Inspections             10 * $73 =           $730

Total overhead costs =                $29,270

Overhead cost per unit = $69.69 ($29,270/420)

Unit Cost of D28K:

Direct materials cost per unit = $48.96

Direct labor cost per unit =        $25.36

Overhead cost per unit =          $69,69

Total unit cost =                         $144.01

7 0
2 years ago
Travis International has a debt payment of $2.34 million that it must make 6 years from today. The company does not want to come
Nataliya [291]

Answer:

$27,692.31

Explanation:

Principle amount = $2.34 million = $2,340,000

Time, n = 6 years = 72 months

Rate of interest = 5.33%

Monthly rate of interest, r = 5.33% ÷ 12 = 0.44% = 0.0044

Compounded monthly

FV of Annuity = ( Monthly deposits ) × { [ ( 1 + r )ⁿ - 1 ] ÷ r }

or

$ 2,340,000 = ( Monthly deposits ) × { [ ( 1 + 0.0044 )⁷² - 1 ] ÷ 0.0044 }

or

$2,340,000 = ( Monthly deposits ) × { [  1.3718 - 1  ] ÷ 0.0044 }

or

$2,340,000 = ( Monthly deposits ) × [ 0.3718 ÷ 0.0044 ]

or

$2,340,000 = ( Monthly deposits ) × 84.5

or

Monthly deposits = $27,692.31

7 0
3 years ago
Read 2 more answers
In august 2016, richard purchased and placed in service an office building costing $753,000, including $134,000 for the land. th
frutty [35]
I think the depreciation will be charged only on the value of the house so that would be $753000-134000=$619000 since the land wouldn't depreciate. The actual amount of depreciation I don't know, just that it will be based on this value of the building on the land.
8 0
3 years ago
Olivia was returning from her break when her boss saw her and stated, "I noticed your break was especially long this afternoon."
mamaluj [8]

The given change in Olivia’s work presentation happened because of Filtering

<u>Explanation: </u>

A communication barrier is something that stops us from accessing and interpreting communications that other people use to communicate their knowledge, thoughts, and ideas.

Filtering is a transmitter that handles information in this way the recipient would be included more favorably. The number of rates in an organization's framework is the main factor in determining of the filtering. Filtering also happens when the recipient of the message enables multiple persons to pass the information before reaching their final destination.

A Few examples of filtering have included a manager who leaves her boss, the vice-president, in the midst of the bad news, with the poor sales statistics from her division.

6 0
3 years ago
Elizabeth Kennedy sells beauty supplies. Her annual demand for a particular skin sparkle is 17,000 units. The cost of placing an
elena-s [515]

Answer:

The minimum cost will be "$214085".

Explanation:

D = 1700 units \\\\S =  \$ 50 \\\\H=  20%\\

i) When quantity = 1-1500,  price = $ 12.50 , and holding price is $12.50 * 20 %= $2.50.

ii) When quantity = 1501 -10,000,  price = $ 12.45 , and holding price is $12.45 * 20 %= $2.49.

iii) When quantity = 10,0001- and more,  price = $ 12.40 , and holding price is $12.40 * 20 %= $2.48.

EOQ= \sqrt{\frac{2DS}{H}} \\\\EOQ1= \sqrt{\frac{2\times 17000\times 50}{2.50}} \\\\EOQ1=824.62 \ \ \ or \ \ \ 825\\

EOQ2= \sqrt{\frac{2\times 17000\times 50}{2.49}} \\\\EOQ1=826.2T \ \ \ or \ \ \ 826\\

EOQ3= \sqrt{\frac{2\times 17000\times 50}{2.48}} \\\\EOQ3=827.93 \ \ \ or \ \ \ 828\\

know we should calculate the total cost of EOQ1 and break ever points (1501 to 10,000)units

total \ cost = odering \ cost + holding \ cost + \ Annual \ product \ cost\\\\total_c  = \frac{D}{Q} \times S +  \frac{Q}{2} \times H + (p \times D) \\\\T_c  = \frac{17000}{825} \times 50+  \frac{825}{2} \times 2.50 + (12.50 \times 17000)\\\\T_c = 1030 .30 +1031.25+212500\\\\T_c =$ 214561.55\\\\

T_c  = \frac{17000}{1501} \times 50+  \frac{1501}{2} \times 2.49 + (12.45 \times 17000)\\\\T_c = 566.28 +1868.74+211650\\\\T_c =$ 214085.02 \ \ \ or \ \ \  $ 214085\\\\

T_c  = \frac{17000}{10001} \times 50+  \frac{10001}{2} \times 2.48 + (12.40 \times 17000)\\\\T_c = 84.99+ 12401.24+210800\\\\T_c =$ 223286.23 \\

The total cost is less then 15001. So, optimal order quantity is 1501, that's why cost is = $214085.

5 0
3 years ago
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