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4 years ago

Write 3 different improper fractions that equal 4 2/3

Mathematics

1 answer:

Semmy [17]4 years ago

6 0

14/3
28/6
56/12
there ya go. =)

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please help please help please help Suppose Karen $1000 that she invests in an account that pays 3% interest compounded annually

mojhsa [17]

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3 years ago

The expression means the product of 5 and the difference of three times r minus 10. If r = 4, the value of the expression is .

Morgarella [4.7K]

Answer:

Step-by-step explanation:

"three times r" = 3r

"three times r minus ten" = 3r - 10

"product of 5 and the difference of three times r minus ten"

= 5 (3r - 10)

given that r = 4,

the expression becomes

5 (3r - 10)

= 5 [3(4) - 10]

= 5 [12 - 10]

= 5 (2)

= 10

4 0

3 years ago

Y=arccos(1/x) Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

2 years ago

I have tried and tried I just cant get one thing to be right

Elis [28]

Vertex: (1,-4)
axis of symmetry: x=1
min
minimum value: y=-4
x intercepts: -1, 3
y intercept: -3

i dont know how to find solutions or roots sorry

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3 years ago

IPod Touch 64 GB On Sale For $299.99 Originally $349.99 _______% Savings

liubo4ka [24]

Answer:

14.286% savings

Step-by-step explanation:

299.99 / 349.99 = 0.8571..

1-0.8571= 14.286

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3 years ago