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2 years ago

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In triangle ABC, m <A=35°, m <B=65°, and c=15. find b round your answer to the nearest tenth

1 answer:

GREYUIT [131]2 years ago

5 0

The answer is 65 because when you add 35+65+15 you get 115 and a triangle is 180 degrees so<span> 180-115=65</span><span>
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SOMEONE HELP!!!

Tasya [4]

Step-by-step explanation:

a) here,

diametre = 19 cm

Area = ?

Now,

Area = pie d

= 22/7 *19

59.71 cm2

Therefore, area = 59.71 sq.cm.

b)

here,

Area = 1000 sq.cm

diametre = ?

Now ,

Area = pie d

1000 = 22/7 *d

7000 = 22 * d ( cross multiply between 7&1000)

7000/22 = d

318.18 = d

Therefore, diametre = 318.18 cm .

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2 years ago

Please help!!!!!

WARRIOR [948]

3)

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2 years ago

A boat travels 336 miles in 22hours (with a constant speed). How far can it travel in 8 hours (with the same speed)?

Sergeeva-Olga [200]

Answer:

122.18 miles.

Step-by-step explanation:

336miles/22hours × x miles/8hours

336 × 8 ÷ 8 = 122.18miles

<em>good luck, i hope this helps :)</em>

8 0

2 years ago

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

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2 years ago

Question from my math test

frutty [35]

Answer:

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Step-by-step explanation:

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Then,

March - April.

But then, the store manager goes from

May - July,

and totally skipped June, therefore making it look like the sales have increased.

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2 years ago