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Leona [35]
3 years ago
11

Find the zeros of the quadratic equation by finding the square root: x2 + 10 = 110.​

Mathematics
1 answer:
icang [17]3 years ago
3 0

Answer:

10

Step-by-step explanation:

x^2+10=110

x=(100)^½

x=10 where:½ is radical

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In Jefferson Middle School, 5% of the sixth graders have red hair. If there are 100 sixth graders, how many have red hair?
k0ka [10]

Answer:

5

Step-by-step explanation:

Take the number of 6th graders and multiply by the percent that have red hair

100 * 5%

100 * .05

5

3 0
3 years ago
Read 2 more answers
Which of the following represent(s) an equation of the line passing through the points A(5, 6) and B(4, 8). Select all that appl
andriy [413]

Answer:

The equations that represent the equation of the line are:

y = -2x + 16 ⇒ A

2x + y = 16 ⇒ D

y - 6 = -2(x - 5) ⇒ E

Step-by-step explanation:

The slope intercept form of the linear equation is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept (y at x = 0)

The formula of the slope is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ The line is passing through points (5 , 6) and (4 , 8)

∴ x_{1} = 5 and  x_{2} = 4

∴ y_{1} = 6 and  y_{2} = 8

- Substitute them in the formula of the slope to find it

∵ m=\frac{8-6}{4-5}=\frac{2}{-1}

∴ m = -2

- Substitute it in the form of the equation

∴ y = -2 x + b

- To find b substitute x and y in the equation by the coordinates

    of any point in the line

∵ x = 5 and y = 6

∴ 6 = -2(5) + b

∴ 6 = -10 + b

- Add 10 to both sides

∴ 16 = b

∴ y = -2 x + 16

∴ The equation of the line is y = -2x + 16

∴ A represents the equation of the line

∵ 2x + y = 16

- Subtract 2x from both sides

∴ y = -2x + 16

∴ D represents the equation of the line

∵ y - 6 = -2(x - 5)

∴ y - 6 = -2x + 10

- Add 6 to both sides

∴ y = -2x + 16

∴ E represents the equation of the line

The equations that represent the equation of the line are:

y = -2x + 16 ⇒ A

2x + y = 16 ⇒ D

y - 6 = -2(x - 5) ⇒ E

7 0
3 years ago
-0.55 as a fraction in simplest form please?
Strike441 [17]
The answer would be -11/20
6 0
3 years ago
Verify which of the following are identities.
ch4aika [34]

Answer:

C

Step-by-step explanation:

Equation 1:

1+\frac{\cos^{2} \theta}{\cot^{2} \theta(1-\sin^{2} \theta)}\\ \\ 1+\frac{\sin^{2} \theta}{\cos^{2} \theta} \\ \\ 1+\tan^{2} \theta \\ \\ \sec^{2} \theta

Equation 2:

15\cos \theta \left(\frac{1}{\cos \theta}-\frac{\cot \theta}{\csc \theta} \right) \\ \\ 15\cos \theta \left(\frac{1}{\cos \theta}-\frac{\cos \theta / \sin \theta}{1/\sin \theta} \right) \\ \\ 15\cos \theta \left(\frac{1}{\cos \theta}-\cos \theta \right) \\ \\ 15\cos \theta \left(\frac{1-\cos^{2} \theta}{\cos \theta} \right) \\ \\ 15(1-\cos^{2} \theta) \\ \\ 15\sin^{2} \theta

6 0
2 years ago
The function f(x)=x^2 -6x+3 is transformed such that g(x)=f(x-2). Find the vertex of g(x).
Lisa [10]

Answer:

g(x) = (x-2)^2 -6(x-2) +3

g(x) = x^2 -4x +4 -6x +12 +3

g(x) = x^2 -10 x +19

g(x) = x^2 -10 x + 25 +19 -25

g(x) = (x-5)^2 -6

y= (x-h)^2 -kk

Where h,k represent the vertex and we got:

(h,k)= (5,6)

(5,6)

Step-by-step explanation:

We have this original function given :

f(x) = x^2 -6x +3

And we want to find the vertex for this new function g(x) = f(x-2) and we have:

g(x) = (x-2)^2 -6(x-2) +3

And solving the square we got:

g(x) = x^2 -4x +4 -6x +12 +3

And adding similar terms we got:

g(x) = x^2 -10 x +19

Now we can complete the square like this:

g(x) = x^2 -10 x + 25 +19 -25

g(x) = (x-5)^2 -6

The general equation is given by:

y= (x-h)^2 -kk

Where h,k represent the vertex and we got:

(h,k)= (5,6)

(5,6)

5 0
4 years ago
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