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strojnjashka [21]

3 years ago

6

Find the height of a parallelogram with base 6.75m and an area of 218.72 square meters

1 answer:

iren [92.7K]3 years ago

7 0

Answer:

32.4 m

Step-by-step explanation:

The formula for the area of a parallelogram is A = L· W.

We know the base (L) and the area (218.72 m²) and need to find the height (W).

Solving A = L · W for W (height), we get:

W = A / L

218.72 m²

Here, W = ---------------- = 32.4 m

6.75 m

The height of the parallelogram is 32.4 m.

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At 5.45p.M .,lixin,khairul and Devil are at the starting point of a 1-km circular path. Lixin Takes 18 minutes to walk one round

sweet [91]

Answer:

$Meeting\ Time = 6:03\ pm$

Step-by-step explanation:

Given

$Start\ Time= 5:45pm$

$Lixin = 18\ min/round$

$Khairul = 360\ seconds/round$

$Devi = 4minutes/2\ rounds$

Required

Determine their next meeting time

First, we need to get their unit rate in minutes per round

$Lixin = 18\ min/round$

$Khairul = 360\ seconds/round$

Convert 360 seconds to minutes

$Khairul = \frac{360}{60} min/round$

$Khairul = 6 min/round$

$Devi = 4minutes/2\ rounds$

Divide by 2/2

$Devi = 2mins/round$

So, we have:

$Lixin = 18\ min/round$

$Khairul = 6 min/round$

$Devi = 2mins/round$

Next, is to determine the LCM of 18, 6 and 2

$18=2 * 3 * 3$

$6 = 2 * 3$

$3 = 3$

Their LCM is:

$LCM = 2 * 3 * 3$

$LCM = 18$

This means that they will meet 18 minutes after their initial time of departure.

So:

$Meeting\ Time = 5:45\ pm + 18\ minutes$

$Meeting\ Time = 6:03\ pm$

3 0

3 years ago

A school plays a series of 6 soccer matches. For each match there are 3 possibilities: a win, a draw or a loss. How

Sphinxa [80]

Answer:

There are 729 possible results are there for the series

Step-by-step explanation:

If we have n trials, each with m possible outcomes, the total number of possible outcomes is:

$T = m^{n}$

In this question:

6 games(trials), so $n = 6$ .

Each with three possible outcomes, so $m = 3$

Then:

$T = 3^{6} = 729$

There are 729 possible results are there for the series

7 0

3 years ago

Write an equation of a line that is parallel to y=-3x+5 that passes through the point (0,-4)

elena55 [62]

Answer:

${ \rm{y = - 3x + 5}}$

Gradient = -3

• Parallel lines have the same gradient, therefore gradient, m is -3

${ \rm{y = mx + c}}$

• At point (0, -4)

${ \rm{ - 4 = ( - 3 \times 0) + c}} \\ \\ { \rm{c = - 4}}$

y intercept is -4

${ \boxed{ \boxed{ \mathfrak{answer : }}{ \rm{\: \: y = - 3x - 4}}}}$

6 0

3 years ago

A. 8.5<br> B. 8.4<br> C. 8.3<br> D. 8.6 <br><br> @mathstudent55

Roman55 [17]

C. 8.3

to solve use cos 32 = 7/x
x = $\frac{7}{cos (32)} =8.25424...$

7 0

3 years ago

A concert hall has 8,000 seats and two categories of ticket prices, $29 and $34. Assume that all seats in each category can be s

Greeley [361]

Using a system of equations, it is found that:

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

--------------------

The variables of the system are:

x, which is the number of $29 tickets sold.
y, which is the number of $34 tickets sold.

Total of 8,000 seats, all can be sold, thus:

$x + y = 8000 \rightarrow x = 8000 - y$

--------------------

For a profit of $255,000, we have that:

$29x + 34y = 255000$

$29(8000 - y) + 34y = 255000$

$5y = 23000$

$y = \frac{23000}{5}$

$y = 4600$

$x = 8000 - 4600 = 3400$

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.

--------------------

For a profit of $271,000, we have that:

$29x + 34y = 271000$

$29(8000 - y) + 34y = 271000$

$5y = 39000$

$y = \frac{39000}{5}$

$y = 7800$

$x = 8000 - 7800= 200$

For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.

--------------------

For a profit of $235,000, we have that:

$29x + 34y = 235000$

$29(8000 - y) + 34y = 235000$

$5y = 3000$

$y = \frac{3000}{5}$

$y = 600$

$x = 8000 - 600 = 7400$

For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

A similar problem is given at brainly.com/question/22826010

3 0

3 years ago