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Anon25 [30]
3 years ago
12

Find the x value do that the line through the points (x,-9) and (0,1) has a slope of -4 PLEASE ANSWER

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

\bf (\stackrel{x_1}{x}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-9)}{0-x}=\stackrel{\stackrel{slope}{\downarrow }}{-4}\implies \cfrac{1+9}{-x}=-4 \\\\\\ \cfrac{10}{-x}=-4\implies 10=4x\implies \cfrac{10}{4}=x\implies \cfrac{5}{2}=x

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forsale [732]
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7 0
1 year ago
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I need help
blondinia [14]

Answer:

b- 13 weeks

Step-by-step explanation:

She makes $550 a week but spends $200 on merchandise so her total weekly is technically $350 in order to earn profit she has to get more than $4500

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3 0
3 years ago
9a - 3 (a - 6) = -6 a=___
leonid [27]
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7 0
3 years ago
You are testing the claim that the mean GPA of night students is different from the mea GPA of day students. You sample 20 night
svetlana [45]

Answer:

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Step-by-step explanation:

Here n= 20

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Level of Significance.= ∝ = 0.01

The hypothesis are formulated as

H0: u1=u2   i.e the GPA of night students is same as the mean GPA of day students

against the claim

Ha: u1≠u2

i.e the GPA of night students is different from the mea GPA of day students

For two tailed test  the critical value is  z ≥ z∝/2= ± 2.58

The test statistic

Z= x`-u/s/√n

z= 2.84-2.55/0.45/√20

z= 0.1441

As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.

8 0
3 years ago
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Kazeer [188]

Answer:

A,D,E

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5t=6t

ii. 2a+2b=4ab

iii. x+3=4x

5 0
3 years ago
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