Answer:
Multiply the coordinates of point P by the scale factor 7/4 to get the coordinates of P'.
Given : P(-5,3)
P' (x,y) = P (-5 x 7/4 , 3 x 7/4)
= P(-8.75, 5.25)
Step-by-step explanation:
Answer:
y = -2x + 6
Step-by-step explanation:
y=mx + c
m is the gradient and c is the y intercept
m = (y 2 - y 1) / (x 2 - x 1) = (2-4) / ( 2-1) = -2
y= -2x + c
To find c, just sub one of the coordinates into the eqn:
By using the coordinates (1,4)
4 = -2(1) + c
c = 6
Therefore, the equation is y = -2x + 6
5u - (-20u) - u - 18u + (-11u) = 10
5u + 20u - u - 18u - 11u = 10
-5u = 10
-5(-2) = 10
So, in conclusion, X, is equal to -2.
If x approach infinity then (x² + 1)/(2x² +1) = 1/2 then lim as x approach infinity
lim y = arccos 1/2 = 1.047
Answer! :
y = -2x + 5
Step by Step! :
slope intercept form:
y = mx + b
m being slope, b being the y intercept.
To find the slope, use this equation:
y^2 - y^1 / x^2 - x^1
Plug in your points.
(-1) - (7) / (3) - (-1)
-8 / 4
-2 is your slope! (y = -2x + b)
To solve for b, plug in any one of your points and solve for b. Let's use (3, -1)
-1 = -2(3) + b
-1 = -6 + b
5 = b
Your new equation is...
y = -2x + 5
